MYSQL资源查询

Question

我首先从MYSQL数据库中获取查询并通过电子邮件发送到我的邮件

MYSQL

$sqll = "SELECT motheremail FROM family WHERE familyId = 1004";
            $email_message = mysql_query($sqll)or die(mysql_error());;

但是，作为电子邮件中的消息，我得到“资源ID＃83”，而不是表格中的内容

任何想法为什么？

Answer 1

您需要获取查询结果。

$sqll = "SELECT motheremail FROM family WHERE familyId = 1004";
$result = mysql_query($sqll)or die(mysql_error());

// Fetch the row from the result set
$row = mysql_fetch_assoc($result);

echo $row['motheremail'];

或者如果需要多行，请在while循环中获取它们：

$sqll = "SELECT motheremail FROM family WHERE familyId = 1004";
$result = mysql_query($sqll)or die(mysql_error());

while ($row = mysql_fetch_assoc($result)) {
  echo $row['motheremail'];
}

Answer 2

mysql_query不会直接返回字符串。你必须使用这样的东西：

$sql = "SELECT `motheremail` FROM `family` WHERE familyId = 1004";
$query = mysql_query($sql) or die (mysql_error());
$message = mysql_fetch_assoc($query)['motheremail'];
echo $message;