在我的一个视图控制器中,我想使用多个选择器。
标题文件:
@interface MyTableController : TTTableViewController <UIActionSheetDelegate, UIPickerViewDataSource, UIPickerViewDelegate>{
IBOutlet UIPickerView *picker1;
IBOutlet UIPickerView *picker2;
NSMutableArray *list1;
NSMutableArray *list2;
}
@property(nonatomic,retain) UIPickerView *picker1, *picker2;
-(IBAction)togglePickerView1;
-(IBAction)togglePickerView2;
@end
实施档案:
@implementation MyTableController
@synthesize picker1, picker2;
int row_index1 = 0;
int row_index2 = 0;
- (void)locationPicker:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent: (NSInteger)component
{
if([pickerView isEqual: picker1]){
row_index1 = row;
}
if([pickerView isEqual: picker2]){
row_index2 = row;
}
}
-(NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView{
if([pickerView isEqual: picker1]){
return 1;
}
if([pickerView isEqual: picker2]){
return 1;
}
return 0;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component{
if([pickerView isEqual: picker1]){
return [list1 count];
}
if([pickerView isEqual: picker2]){
return [list2 count];
}
return 0;
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent: (NSInteger)component{
return [list objectAtIndex:row];
if([pickerView isEqual: picker1]){
return [list1 objectAtIndex:row];
}
if([pickerView isEqual: picker2]){
return [list2 objectAtIndex:row];
}
return nil;
}
-(void)actionSheet:(UIActionSheet *)actionSheet didDismissWithButtonIndex:(NSInteger)buttonIndex {
}
- (void)willPresentActionSheet:(UIActionSheet *)actionSheet {
if (actionSheet.tag == 111) {
picker1 = [[UIPickerView alloc] initWithFrame:CGRectMake(0, 40, 320, 216)];
picker1.showsSelectionIndicator = YES;
picker1.dataSource = self;
picker1.delegate = self;
//Add picker to action sheet
[actionSheet addSubview:picker1];
[picker1 release];
}else if(actionSheet.tag == 222){
picker2 = [[UIPickerView alloc] initWithFrame:CGRectMake(0, 40, 320, 216)];
picker2.showsSelectionIndicator = YES;
picker2.dataSource = self;
picker2.delegate = self;
//Add picker to action sheet
[actionSheet addSubview:picker2];
[picker2 release];
}
//Gets an array af all of the subviews of our actionSheet
NSArray *subviews = [actionSheet subviews];
[[subviews objectAtIndex:1] setFrame:CGRectMake(20, 266, 280, 46)];
[[subviews objectAtIndex:2] setFrame:CGRectMake(20, 317, 280, 46)];
}
-(IBAction)togglePickerView1{
UIActionSheet *asheet = [[UIActionSheet alloc] initWithTitle:NSLocalizedString(@"FLT", nil) delegate:self cancelButtonTitle:NSLocalizedString(@"CANCEL", nil) destructiveButtonTitle:nil otherButtonTitles:NSLocalizedString(@"PICK", nil), nil];
[asheet setTag:111];
[asheet showInView:[self.view superview]]; //note: in most cases this would be just self.view, but because I was doing this in a tabBar Application, I use the superview.
[asheet setFrame:CGRectMake(0, 117, 320, 383)];
[asheet release];
}
-(IBAction)togglePickerView2{
//...
[asheet setTag:222];
//...
}
- (void)loadView {
[super loadView];
}
-(void)viewDidLoad{
UIBarButtonItem *item1 = [[UIBarButtonItem alloc] initWithTitle:@"Button1" style:UIBarButtonItemStyleBordered target:self action:@selector(togglePickerView1)];
UIBarButtonItem *item2 = [[UIBarButtonItem alloc] initWithTitle:@"Button2" style:UIBarButtonItemStyleBordered target:self action:@selector(togglePickerView2)];
NSArray *myToolbarItems = [[NSArray alloc] initWithObjects: item1, item2, nil];
[self setToolbarItems: myToolbarItems];
[myToolbarItems release];
list1 = [[NSMutableArray alloc] init];
[list1 addObject:@"--"];
[list1 addObject:@"Test1"];
list2 = [[NSMutableArray alloc] init];
[list2 addObject:@"--"];
[list2 addObject:@"Test2"];
}
@end
我的问题是无论我按哪个按钮,它总是被触发的picker1。问题出在哪里?
答案 0 :(得分:2)
您正在成功创建两个不同的选择器,并且每次都显示正确的选择器。
问题是,每个选择器都有相同的数据。
数据源titleForRow...
方法的第一行是:
return [list objectAtIndex:row];
这会通过返回值来结束数据源方法的执行,因此无论代码的其余部分如何,两个选择器都将始终显示相同的数据。上面的代码中没有声明list
,所以我不确定你在屏幕上看到了什么。
我使用上面的代码构建了一个示例项目,并确认这是问题所在。删除该行会为您提供两个不同的选择器,每个选择器具有不同的内容。