JTable,JComboBox使用自定义对象

时间:2012-01-10 14:16:36

标签: java swing jtable jcombobox

如果您将JComboBox放在JTable和String []数组中给JComboBox,一切正常。 Buf如果您将自己的数据类型放到JComboBox中,则选择同一列中的值会变得复杂。这是official example。尝试更改以下部分:

JComboBox comboBox = new JComboBox();
comboBox.addItem("Snowboarding");
comboBox.addItem("Rowing");
comboBox.addItem("Knitting");
comboBox.addItem("Speed reading");
comboBox.addItem("Pool");
comboBox.addItem("None of the above");
sportColumn.setCellEditor(new DefaultCellEditor(comboBox));

分为:

JComboBox comboBox = new JComboBox();
comboBox.addItem(new Test("Snowboarding"));
comboBox.addItem(new Test("Rowing"));
comboBox.addItem(new Test("Knitting"));
comboBox.addItem(new Test("Speed reading"));
comboBox.addItem(new Test("Pool"));
comboBox.addItem(new Test("None of the above"));
sportColumn.setCellEditor(new DefaultCellEditor(comboBox));

并创建新数据类型:

public class Test {
    private String name;

    public Test(String name) {
        this.name = name;
    }

    @Override
    public String toString() {
        return name;
    }
}

你会看到,当你点击女巫中的表格单元格时,会有一个带有自定义数据类型的JComboBox。自动选择第一列单元格的值。如何解决这个问题?

编辑1:我添加了SSCCE。

主类:

import java.awt.BorderLayout;

public class windw extends JFrame {

    private JPanel contentPane;
    private JTable table;

    public static void main(String[] args) {
        EventQueue.invokeLater(new Runnable() {
            public void run() {
                try {
                    windw frame = new windw();
                    frame.setVisible(true);
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        });
    }

    public windw() {
        setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        setBounds(100, 100, 450, 300);
        contentPane = new JPanel();

        contentPane.setLayout(new BorderLayout(0, 0));
        setContentPane(contentPane);

        table = new JTable();
        String[] grupes2 = new String[3];
        grupes2[0] = "first";
        grupes2[1] = "second";
        grupes2[2] = "third";

        table.setModel(new DefaultTableModel(
            new Object[][] {
                {new JComboBox<String>(grupes2)},
                {new JComboBox<String>(grupes2)},
                {new JComboBox<String>(grupes2)},
                {new JComboBox<String>(grupes2)},
                {new JComboBox<String>(grupes2)},
                {new JComboBox<String>(grupes2)},
                {new JComboBox<String>(grupes2)},
            },
            new String[] {
                "Column name"
            }
        ));
        TableColumn sportColumn = table.getColumnModel().getColumn(0);
        sportColumn.setCellEditor(new DefaultCellEditor(new JComboBox<String>(grupes2)));
        sportColumn.setCellRenderer(new Renderer(grupes2));
        contentPane.add(table, BorderLayout.CENTER);
    }

}

渲染器:

import java.awt.Component;

import javax.swing.JComboBox;
import javax.swing.JTable;
import javax.swing.table.TableCellRenderer;

public class Renderer extends JComboBox implements TableCellRenderer {
    public Renderer(String[] items) {
        super(items);
    }

    public Component getTableCellRendererComponent(JTable table, Object value,
            boolean isSelected, boolean hasFocus, int row, int column) {
        if (isSelected) {
            setForeground(table.getSelectionForeground());
            super.setBackground(table.getSelectionBackground());
        } else {
            setForeground(table.getForeground());
            setBackground(table.getBackground());
        }

        // Select the current value
        setSelectedItem(value);
        return this;
    }
}

1 个答案:

答案 0 :(得分:8)

问题是你的TableModel存储一个String对象,而ComboBox包含一个Test对象。这些对象不相等,因此没有要选择的项目,看起来第一个会自动突出显示。

将您的代码更改为以下内容,您将看到与未知字符串相同的问题:

{"Joe", "Brown", "Pool?????", new Integer(10), new Boolean(false)}

要解决问题,我猜您需要执行以下操作:

{"Joe", "Brown", new Test("Pool"), new Integer(10), new Boolean(false)}

然后,您需要在Test类中实现equals()方法,以比较两个组件的name属性。同样,您需要实现hashcode()方法。

将来,正如安德鲁建议的那样,请将您的SSCCE包含在您的问题中,因为我们没有时间复制/粘贴/编辑和测试代码,因为我们永远不知道我们是否完全按照您的方式执行此操作。