Question

我有一个功能，用户不经常上传他们的数据csv，可能包括大约200个记录和80个字段，可能记录在6000 django数据库对象的区域。

我想让他们预览数据，所以我在views.py中有以下代码（在这里缩短了......）：

@login_required
def import_assessments(request):
    import csv
    if request.method == 'POST':
        form = AssessmentUploadForm(request.POST, request.FILES)
        if form.is_valid():
            # handle standard form fields
            year = int(request.POST['date_year'])
            ...
            # handle uploaded .csv file
            reader = csv.reader(request.FILES['file_upload'])
            data = csv.DictReader(request.FILES['file_upload'])
            # make some empty lists
            unmatched_pupils = []
            pupil_tuples = []
            csv_errors = []
            # make a list of included objectives, derived from column headings
            ...
            # handle the pupil data rows
            for row in data:
                # build a list of objective,assessment tuples for this pupil
                assessments_list = []
                for string in objective_strings:
                    theobjective = included_objectives[string]
                    assessments_list.append((theobjective, row[string]))
                # look the pupil up, and in any case add this new tuple to the pupil's results
                firstname = row["First name"]
                surname = row["Surname"]
                tutor_group = row["Tutor group"]
                try:
                    if tutor_group:
                        thepupil = Pupil.objects.get(firstname__iexact = firstname, surname__iexact = surname, tutor_group__iexact = tutor_group)
                    else:
                        thepupil = Pupil.objects.get(firstname__iexact = firstname, surname__iexact = surname)
                except Pupil.DoesNotExist:           
                    unmatched_pupils.append(
                    (
                    (firstname,surname,tutor_group),
                    assessments_list
                    ))
                ...
                else:
                    pupil_tuples.append(
                        (
                        thepupil,
                        assessments_list
                        ))

            # now create errors
            if unmatched_pupils:
                if len(unmatched_pupils) >=2:
                    themessage = 'The following pupils could not be identified in the database:'
                else:
                    themessage = 'The following pupil could not be identified in the database:'
                csv_errors.append({
                    'type': 'unmatched_pupils',
                    'class': 'error',
                    'message': themessage,
                    'offenders': unmatched_pupils,
                    'instruction': 'Check for typing errors in the name or tutor group. If pupils are new, you can add them individually, or import whole year groups using the links below.',
                    })
            ...
            # render a preview page
            return render_to_response('import_preview.html', locals(), context_instance=RequestContext(request))

        else:
            form = AssessmentUploadForm(request.POST)
    else:
        form = AssessmentUploadForm()
    return render_to_response('assessments_upload.html', locals(), context_instance=RequestContext(request))

我的真实视图功能有点长（163行），有额外的代码来检查多个可能的瞳孔匹配，以及csv列标题中所有潜在的拼写错误和意外重复。由于这些都不是表单错误，我将它们发送到在csv_errors列表中打包的import_preview.html文件，在那里向他们提供建议。

如果没有错误，我的预览页面会显示一个数据表，所有数据都打包在pupil_tuples中。我的下一步是添加一个链接/按钮将所有这些保存到数据库。我在第一次测试此上载时（在我介绍所有错误检查之前）使用的传统代码行是：

Assessment.objects.get_or_create(objective=theobjective, pupil=thepupil, teacher=theteacher, status=status, date=thedate)

我想知道这一切的布局应该是什么。我的数据已全部打包在pupil_tuples列表中，我只想get_or_create，但我应该使用指向新视图功能的链接，新表单，if request.method == 'POST'码？

PS我还真的需要分别加载csv.reader和csv.DictReader吗？这是一个资源问题吗？我想迭代所有标题作为列表，检查重复，我不认为DictReader会让我这样做。但是我希望DictReader的所有便利用于我的其余部分。

Django csv导入预览

0 个答案: