使用prepareForSegue传递UIWebView请求

Question

我是IOS和Objective C的新手。 场景是我有2个按钮，打开（带有segue）2个包含UIWebview的视图控制器。 我认为最好用1 UIWebView来做，所以我试图传递webvew的请求对象并只使用一个webview控制器。

所以我得到了wwwBtn（打开网站的UIButton）和fbBtn（转到Facebook网址的UIButton）我的viewController和包含UIWebView的wwwWebViewController。

我是这样做的。

viewController.h文件：

@interface ViewController : UIViewController {
    UIButton *wwwBtn;
    UIButton *fbButton;
}
@property (retain, nonatomic) IBOutlet UIButton *wwwBtn;
@property (retain, nonatomic) IBOutlet UIButton *fbBtn;

ViewController.m文件：

#import "ViewController.h"
#import "wwwWebViewController.h"

@implementation ViewController

@synthesize wwwBtn;
@synthesize fbBtn;

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{        
    if ([[segue identifier] isEqualToString:@"web"]) {
            NSString *urlstr=@"http ://www.google.com";
            wwwWebViewController *vc = [segue destinationViewController];
            vc.urlStr = urlstr;
        } else if ([[segue identifier] isEqualToString:@"fb"]) { 
            NSString *urlstr = @"http://www.facebook.com";
            wwwWebViewController *vc = [segue destinationViewController];
            vc.urlStr = urlstr;
        }
    }

wwwWebViewController.h文件：

@interface wwwWebViewController : UIViewController {
    UIWebView *webView;
}

@property (retain, nonatomic) IBOutlet UIWebView *webView;

wwwWebViewController.m文件：

    - (void)viewDidLoad
   {
        NSURL *url = [NSURL URLWithString:urlStr];
        NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
        [webView loadRequest:requestObj];
        [super viewDidLoad];
    }

Answer 1

执行以下操作，您将此类分配给目标UIViewControllers，您需要将 NSString * urlstr 传递给它们：

WebViewController.h

@interface WebViewController : UIViewController {
    NSString *urlstr;
}

@property (strong, nonatomic) IBOutlet UIWebView *WebView;
@property (strong, nonatomic) NSString *urlstr;

WebViewController.m

@implementation WebViewController

@synthesize WebView;
@synthesize urlstr;

- (void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view.

    NSURL *url = [NSURL URLWithString:urlstr];
    NSURLRequest *requestObj = [NSURLRequest requestWithURL:url];
    [self.WebView loadRequest:requestObj];

}

现在是时候从我的主故事板类InfoViewController创建两个segue到目标类WebViewController，在我的例子中我创建了三个segues但只有两个使用了WebViewController类。

您还要为segue提供一个空间标识符，以便在主类InfoViewController中以编程方式定位它们。

让我们看一下InfoViewController：UITableViewController的外观：

InfoViewController.m

#import "InfoViewController.h"
#import "WebViewController.h"

@interface InfoViewController ()

@end

@implementation InfoViewController

@synthesize AboutCell = _AboutCell;
@synthesize CGCell = _CGCell;
@synthesize FTACell = _FTACell;

- (void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view from its nib.
}

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    UITableViewCell *AboutCellClicked = [self.tableView cellForRowAtIndexPath:indexPath];
    UITableViewCell *CGCellClicked = [self.tableView cellForRowAtIndexPath:indexPath];
    UITableViewCell *FTACellClicked = [self.tableView cellForRowAtIndexPath:indexPath];

    if (AboutCellClicked == _AboutCell) {
        [self performSegueWithIdentifier:@"AboutPush" sender:self];
    } else if (CGCellClicked == _CGCell) {
        [self performSegueWithIdentifier:@"CGPush" sender:self];
    } else if (FTACellClicked == _FTACell) {
        [self performSegueWithIdentifier:@"FTAPush" sender:self];
    }

}

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    WebViewController *webController = [[WebViewController alloc] init];

    if ([[segue identifier] isEqualToString:@"CGPush"]) {
        NSString *urlstr=@"http://www.google.com";
        webController = [segue destinationViewController];
        webController.urlstr = urlstr;
    } else if ([[segue identifier] isEqualToString:@"FTAPush"]) {
        NSString *urlstr=@"http://www.yahoo.com";
        webController = [segue destinationViewController];
        webController.urlstr = urlstr;
    }
}

@end

我希望这可以解决您的问题，如果您有任何疑问，请不要犹豫。