如何从具有特定开头标题的HTML链接中检索网址? e。:
<a href="http://urltoretrieve.ext/" title="specific title rest of all title">something</a>
<a href="http://otherurl.ext/" title="a generic title">somethingelse</a>
并使用PHP来检索:
http://urltoretrieve.ext/
谢谢!
答案 0 :(得分:3)
您可以使用https://gist.github.com/1358174和此XPath:
//a[starts-with(@title, "specific title")]/@href
此查询表示:
//a find all a elements in the html
[ that
starts-with(
@title has a title attribute
'specific-title' starting with this value
)
]
/@href and return their href attribute
示例(demo):
$result = xpath_match_all(
'//a[starts-with(@title, "specific title")]/@href',
$yourHtmlAsString
);
输出:
array(2) {
[0]=>
array(1) {
[0]=>
string(38) "<href>http://urltoretrieve.ext/</href>"
}
[1]=>
array(1) {
[0]=>
string(25) "http://urltoretrieve.ext/"
}
}
结果是一个数组,其中包含找到的属性节点的序列化innerHTML和outerHTML。如果您不了解节点是什么,请检查DOMDocument in php