Question

如何制作一个下拉菜单，反映数据库中相应列中存储的内容？

我有一个生日选择的下拉菜单，它可以更新数据库但是在刷新的选择菜单中返回默认选项，因为我的所有文本字段都正在提取数据库数据。

我的表格：

    <%= form_for @profile, :remote => true,  do |f| %>
Username: <%= @profile.user.username %><br />
URL: http://site.com/<%= @profile.user.username %><br />
First Name: <%= f.text_field :first_name,   %><br />
Last Name: <%= f.text_field :last_name,  %><br />
I am <%= f.select :gender, options_for_select([['Select Gender', ''],['Male','m'],['Female','f']], "#{@profile.gender if @profile.gender}") %><br />
My birthday: 
<%= f.select :day, options_for_select(Profile::DAYS), :include_blank => "Day" %>
<%= f.select :month, options_for_select(Profile::MONTHS), :include_blank => "Month" %>
<%= f.select :year, options_for_select(Profile::YEAR_RANGE), :include_blank =>"Year" %><br />
<%= f.submit 'update' %><br />
<% end %>

有什么线索我错过了什么？亲切的问候

这是我的模特：

class Profile < ActiveRecord::Base

  belongs_to :user

   attr_accessor   :password, :day, :month, :year
   attr_accessible :first_name, :last_name, :gender, :motd, :day, :month, :year

  # Local Variables
  # Regex Variables
  email_regex = /\A[\w+\-.]+@[a-z\d\-.]+\.[a-z]+\z/i
  alpha_regex = /^[a-zA-Z]*$/
  alpha_numeric_regix = /^[a-zA-Z0-9_]*$/

  MONTHS = ["January", 1], ["February", 2], ["March", 3], ["April", 4], ["May", 5], ["June", 6], ["July", 7], ["August", 8], ["September", 9], ["October", 10], ["November", 11], ["December", 12]
  DAYS = ["01", 1], ["02", 2], ["03", 3], ["04", 4], ["05", 5], ["06", 6], ["07", 7], ["08", 8], ["09", 9], ["10", 10], ["11", 11], ["12", 12], ["13", 13], ["14", 14], ["15", 15], ["16", 16],
        ["17", 17], ["18", 18], ["19", 19], ["20", 20], ["21", 21], ["22", 22], ["23", 23], ["24", 24], ["25", 25], ["26", 26], ["27", 27], ["28", 28], ["29", 29], ["30", 30], ["31", 31]
  START_YEAR = Time.now.year - 111
  END_YEAR = Time.now.year
  YEAR_RANGE = START_YEAR..END_YEAR


    #Form Validation
    validates :first_name,    :presence      => true,
                              :length        => { :minimum => 2, :maximum => 15 },
                              :format        => {
                                                  :with => alpha_regex,
                                                  :message => "Your first name must contain letters only"
                                                }

    validates :last_name,     :presence      => true,
                              :length        => { :minimum => 2, :maximum => 15 },
                              :format        => {  
                                                  :with => alpha_regex,
                                                  :message => "Your last name must contain letters only"
                                                }

    validates :gender,        :presence      => true,
                              :inclusion     => { 
                                                  :in => %w( m f ), :message => "Are you male or female?"
                                                }



  before_save :prepare_birthday

validate :validate_birthday # if :birthday == nil


private
def prepare_birthday
  begin
    unless year.blank? # in order to avoid Year like 0000
      self.birthday = Date.new(self.year.to_i, self.month.to_i, self.day.to_i)
    end
      rescue ArgumentError
    false
  end
end

def validate_birthday
  errors.add(:birthday, "Birthday is invalid") unless prepare_birthday
end
end

从控制器更新方法

 def update

   respond_to do |format|

     if @profile.update_attributes(params[:profile])

       format.js   { render :js => "window.location = '#{settings_edit_profile_path}'" } 
       flash[:success] = "Profile updated" 
     else
      format.js   { render :form_errors }

    end
  end
end

Answer 1

你不应该那样做那不是应该的方式。在rails中，您应该使用date_select表单助手。 =＆GT; http://api.rubyonrails.org/classes/ActionView/Helpers/DateHelper.html#method-i-date_select当您使用此帮助程序时，它将自动用于创建和更新对象！

另一种可能性是使用jQuerUI datepicker，这也很棒。

如何使下拉菜单反映存储在数据库中相应列的内容？

1 个答案: