Question

我有一个rss xml feed.my xml feed

     <?xml version="1.0" encoding="UTF-8" ?>

- <!--  Generated on Sat, 17 Dec 2011 16:40:23 +0530 
  --> 

- <rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom">

- <channel>

  <atom:link href="http://www.business-standard.com/rss/rss_icon.png" rel="self" type="application/rss+xml" /> 

- <title>

- <![CDATA[ Markets & Investing ->News Now
  ]]> 

  </title>

  <link>http://www.business-standard.com/</link> 

  <description>The latest news from India's most respected business daily.</description> 
  <language>en-us</language> 

  <managingEditor>webtech@bsmail.in (Webmaster)</managingEditor> 

  <webMaster>webtech@bsmail.in (Webmaster)</webMaster> 

  <generator>PHP RSS Feed Generator</generator> 

- <image>

  <url>http://www.business-standard.com/india/images/logo_08.jpg</url>

  <title>Business-Standard</title> 

  <link /> 


  <width>248</width> 

  <height>146</height> 

  </image>

- <item>

- <title>

- <![CDATA[ Gold snaps 5-day losing streak, gains Rs 75
  ]]> 

  </title>

- <description>
- <![CDATA[ Snapping five-day losing streak, gold prices recovered Rs 75 to Rs 27,840 per 10 gram in the national capital today on buying at lower levels amid firm trend overseas.
  ]]> 
  </description>
  <link>http://www.business-standard.com/india/news/gold-snaps-5-day-losing-streak-gains-rs-75/153154/on</link> 
  <pubDate>Sat, 17 Dec 2011 15:38:06 +0530</pubDate> 
  <guid isPermaLink="true">http://www.business-standard.com/india/news/gold-snaps-5-day-losing-streak-gains-rs-75/153154/on</guid> 
  </item>
-

Answer 1

创建如下函数：

public List<string> listOfFeeds()
{
List<string> lst=new List<string>();
lst.add("FEED1");
lst.add("FEED2");
lst.add("FEED3");
return  lst;
}

希望以上例子可以帮助你。如果没有，请解释你想要的东西。

如何在Web服务中返回列表

1 个答案: