Question

我正在尝试将echo -e "a b\nc\nd e"之类的命令的输出转换为数组。

X=( $(echo -e "a b\nc\nd e") )

为每个新行和空格字符拆分输入：

$ echo ${#X[@]}
> 5

for i in ${X[@]} ; do echo $i ; done
a
b
c
d
e

结果应为：

for i in ${X[@]} ; do echo $i ; done
a b
c
d e

Answer 1

您需要先将内部字段分隔符变量（IFS）更改为换行符。

$ IFS=$'\n'; arr=( $(echo -e "a b\nc\nd e") ); for i in ${arr[@]} ; do echo $i ; done
a b
c
d e

Answer 2

将IFS设置为newline。默认情况下，它是space。

[jaypal:~] while IFS=$'\n' read -a arry; do 
echo ${arry[0]}; 
done < <(echo -e "a b\nc\nd e")
a b
c
d e

Answer 3

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如何在bash中逐行将命令输出转换为数组？

3 个答案: