Question

我有一个mysql查询，它试图加入表格，将两个表格中的数据显示在网页上的一个表格上？

<?php
include 'library/connect.php';
$result = mysql_query("SELECT * FROM meetings INNER JOIN rooms USING ('room', 'date', 'time' ) ");

echo "<table border='1'><tr><th>Title</th><th>Chairman</th><th>Secretary</th><th>Terms of Reference</th><th>Named membership</th><th>Occurences</th><th>Room</th><th>Date</th><th>Time</th></tr>";

while($row = mysql_fetch_array($result))
{
        echo "<tr>";
        echo "<td>" . $row['title']. "</td>";
        echo "<td>" . $row['chairman']. "</td>";
        echo "<td>" . $row['secretary']. "</td>";
        echo "<td>" . $row['termsOfReference']. "</td>";        
        echo "<td>" . $row['occurences']. "</td>";
        echo "<td>" . $row['room']. "</td>";
        echo "<td>" . $row['date']. "</td>";
        echo "<td>" . $row['time']. "</td>";

echo "</tr>";
}
echo "</table>";
include 'library/closedb.php';
?>

我是否需要某个表ID？

Answer 1

我怀疑date和time是rooms表中的列，所以它们不应该是JOIN条件的一部分。尝试：

SELECT * 
    FROM meetings m
        INNER JOIN rooms r
            ON m.room = r.room

你怎么加入两张桌子

1 个答案: