Json规范格式： InfoVis-loading and serving JSON data
我有这个php数组：$ my_array：
Array
(
[item_1] => Array
(
[id] => item_1_ID
[name] => item_1_NAME
[data] => item_1_DATA
[children] => Array
(
[door] => Array
(
[id] => door_ID
[name] => door_NAME
[data] => door_DATA
[children] => Array
(
[mozart] => Array
(
[id] => mozart_ID
[name] => mozart_NAME
[data] => mozart_DATA
[children] => Array
(
[grass] => Array
(
[id] => grass_ID
[name] => grass_NAME
[data] => yes
)
[green] => Array
(
[id] => green_ID
[name] => green_NAME
[data] => no
)
[human] => Array
(
[id] => human_ID
[name] => human_NAME
[data] => human_DATA
[children] => Array
(
[blue] => Array
(
[id] => blue_ID
[name] => blue_NAME
[data] => blue_DATA
[children] => Array
(
[movie] => Array
(
[id] => movie_ID
[name] => movie_NAME
[data] => yes
)
)
)
)
)
)
)
)
)
[beat] => Array
(
[id] => beat_ID
[name] => beat_NAME
[data] => yes
)
[music] => Array
(
[id] => music_ID
[name] => music_NAME
[data] => no
)
)
)
)
{
"item_1": {
"id": "item_1_ID",
"name": "item_1_NAME",
"data": "item_1_DATA",
"children": {
"door": {
"id": "door_ID",
"name": "door_NAME",
"data": "door_DATA",
"children": {
"mozart": {
"id": "mozart_ID",
"name": "mozart_NAME",
"data": "mozart_DATA",
"children": {
"grass": {
"id": "grass_ID",
"name": "grass_NAME",
"data": "yes"
},
"green": {
"id": "green_ID",
"name": "green_NAME",
"data": "no"
},
"human": {
"id": "human_ID",
"name": "human_NAME",
"data": "human_DATA",
"children": {
"blue": {
"id": "blue_ID",
"name": "blue_NAME",
"data": "blue_DATA",
"children": {
"movie": {
"id": "movie_ID",
"name": "movie_NAME",
"data": "yes"
}
}
}
}
}
}
}
}
},
"beat": {
"id": "beat_ID",
"name": "beat_NAME",
"data": "yes"
},
"music": {
"id": "music_ID",
"name": "music_NAME",
"data": "no"
}
}
}
}
但是对InfoVis来说，当前的json输出（json_encode（$ my_array））有3个问题：
让我指出问题所以也许你可以帮助一个函数来转换这个json字符串：
看到这片json_encode（$ my_array）输出：
{
"item_1": {
"id": "item_1_ID",
"name": "item_1_NAME",
"data": "item_1_DATA",
"children": {
"door": {
"id": "door_ID",
{
"item_1": {
我们必须删除这些键，例如：“item_1”：
"children": {
"door": {
"id": "door_ID",
正确的代码应该是：
"children": [
{
"id": "door_ID",......
“门”：被删除了...因为它是一把钥匙
“孩子们”：{=＆gt;成为“”孩子“：[
"children": [
{
"id": "grass_ID",
"name": "grass_NAME",
"data": "yes"
},
{
"id": "green_ID",
"name": "green_NAME",
"data": "no"
}
]
json = {
id: "node02",
name: "0.2",
children: [{
id: "node13",
name: "1.3",
children: [{
id: "node24",
name: "2.4"
}, {
id: "node222",
name: "2.22"
}]
}, {
id: "node125",
name: "1.25",
children: [{
id: "node226",
name: "2.26"
}, {
id: "node237",
name: "2.37"
}, {
id: "node258",
name: "2.58"
}]
}, {
id: "node165",
name: "1.65",
children: [{
id: "node266",
name: "2.66"
}, {
id: "node283",
name: "2.83"
}, {
id: "node2104",
name: "2.104"
}, {
id: "node2109",
name: "2.109"
}, {
id: "node2125",
name: "2.125"
}]
}, {
id: "node1130",
name: "1.130",
children: [{
id: "node2131",
name: "2.131"
}, {
id: "node2138",
name: "2.138"
}]
}]
};
理解是否清楚？
希望任何人都可以帮助我..我正在研究这几天！
谢谢。答案 0 :(得分：4)
试试这个快速转换功能
function fixit($yourArray) {
$myArray = array();
foreach ($yourArray as $itemKey => $itemObj) {
$item = array();
foreach ($itemObj as $key => $value) {
if (strtolower($key) == 'children') {
$item[$key] = fixit($value);
} else {
$item[$key] = $value;
}
}
$myArray[] = $item;
}
return $myArray;
}
$fixed = fixit($my_array);
$json = json_encode($fixed);
答案 1 :(得分：2)
这是记录在案的行为。当JSON使用json_encode进行字符串化时，关联数组将生成对象文字。更新原始数组结构以表示所需的结果，而不是修改生成的JSON表示，或者为json_encode包装每个对象的自己的解决方案。
编辑：尝试清理操作
$original = <your original data-array>; // assumed, I reversed your encoded JSON as test data
// Start by stripping out the associative keys for level 1
$clean = array_values($original);
// Then recursively descend array, and do the same for every children-property encountered
function &recursiveChildKeysCleaner(&$arr) {
// If $arr contains 'children'...
if (array_key_exists('children', $arr)) {
/// ...strip out associative keys
$arr['children'] = array_values($arr['children']);
// ...and descend each child
foreach ($arr['children'] as &$child) {
recursiveChildKeysCleaner($child);
}
}
return $arr;
}
foreach ($clean as &$item) {
recursiveChildKeysCleaner($item);
}
unset($item);
echo json_encode($clean);
[{
"id": "item_1_ID",
"name": "item_1_NAME",
"data": "item_1_DATA",
"children": [{
"id": "door_ID",
"name": "door_NAME",
"data": "door_DATA",
"children": [{
"id": "mozart_ID",
"name": "mozart_NAME",
"data": "mozart_DATA",
"children": [{
"id": "grass_ID",
"name": "grass_NAME",
"data": "yes"
},
{
"id": "green_ID",
"name": "green_NAME",
"data": "no"
},
{
"id": "human_ID",
"name": "human_NAME",
"data": "human_DATA",
"children": [{
"id": "blue_ID",
"name": "blue_NAME",
"data": "blue_DATA",
"children": [{
"id": "movie_ID",
"name": "movie_NAME",
"data": "yes"
}]
}]
}]
}]
},
{
"id": "beat_ID",
"name": "beat_NAME",
"data": "yes"
},
{
"id": "music_ID",
"name": "music_NAME",
"data": "no"
}]
}]
答案 2 :(得分：2)
PHP不区分数组（数字键）和关联数组（字符串键）。他们都只是阵列。 Javascript有区别。由于您使用的是字符串键，因此必须将它们作为JS中的对象（{}）来完成。
你不能告诉json_encode忽略数组中的键（例如你的'children'子数组）。这意味着生成的JSON NOT 与原始PHP结构相同 - 您现在已经更改了键名。
您必须处理数组并将所有子子数组键转换为数字：
grass -> 0
green -> 1
etc...
这样json-encode就可以看到它是一个数字键控的PHP数组，这意味着它将生成一个实际的javavscript数组（[]），而不是一个对象（{}）。
另一种方法是编写自己的JSON编码器，为您即时执行此操作。