Question

我怎样才能在这个字符串中得到这2个日期？

FROM 2011-08-01 00:00至2011-08-31 23:59（当地时间）2011-07-15 20时43分

我希望这个日期2011-08-01 00:00和2011-08-31 23:59

Answer 1

日期1：@"(?<=FROM )\d{4}-\d{2}-\d{2} \d{2}:\d{2}"

日期2：@"(?<=TO )\d{4}-\d{2}-\d{2} \d{2}:\d{2}"

Answer 2

应该这样做：

    var dateRegex = @"\d{4}-\d{2}-\d{2} \d{2}:\d{2}";
    var regex = new Regex(@"FROM (" + dateRegex + @") TO (" + dateRegex + @") \(Local Time\) .*$");
    var text = @"FROM 2011-08-01 00:00 TO 2011-08-31 23:59 (Local Time) 2011-07-15 20:43";
    var match = regex.Match(text);
    if (match.Success)
    {
        Console.WriteLine("1: " + match.Groups[1].Value.ToString());
        Console.WriteLine("2: " + match.Groups[2].Value.ToString());
    }

Answer 3

这应该给你你需要的东西（我假设字符串将始终采用这种格式 - 所以没有错误处理）：

string text = "FROM 2011-08-01 00:00 TO 2011-08-31 23:59 (Local Time) 2011-07-15 20:43";

Regex r = new Regex(@"(?<=FROM)(.*?)(?=\()",
                  RegexOptions.Singleline | RegexOptions.IgnoreCase);

string[] dates = r.Split(text).GetValue(1).ToString().Trim().Split(' ');

string date1 = dates[0].ToString() + " " + dates[1].ToString();
string date2 = dates[3].ToString() + " " + dates[4].ToString();

从字符串中获取日期时间

3 个答案: