我想从其他类访问主类中创建的值的hashmap集合。我已经按照它的步骤进行了操作但是我只在子类中获得空值。这是代码
public class SoapTester extends Activity {
private static final String TAG = "Test";
public HashMap<String, String> map = new HashMap<String, String>();
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
map.put("year", "Apple");
map.put("make", "Mango");
map.put("model", "Grape");
map.put("style", "Orange");
map.put("series", "Peach");
}
public HashMap<String, String> getHashmap() {
Log.v(TAG, "map2: E" + map);
return map;
}
public void setHashmap(HashMap<String, String> map) {
this.map = map;
getHashmap();
Log.v(TAG, "map1: E" + map);
}
}
//子类
public class Tradein extends Activity {
private static final String TAG = "Test";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.tradein);
SoapTester ex = new SoapTester();
HashMap<String, String> hm = ex.getHashmap();
Log.v(TAG, "hm: " + hm);//Getting Null Value here
}
}
我错过了什么吗?
答案 0 :(得分:8)
使HashMap静态
public static HashMap<String, String> map = new HashMap<String, String>();
通过这种方式,我们可以随意更改任何活动中的值,无论各种活动之间的确切控制流程如何。
请注意,只有在您不关心应用程序中同一活动(类)的多个副本的实例化时才能使用此技巧,这是最容易实现的
第2步:Android; Implementing global state; share data between Activities and across your application
答案 1 :(得分:1)
不是答案,只是一试。
我对andriod的实施一无所知。但这是我的尝试。
SoapTester ex = new SoapTester();
ex.onCreate(savedInstanceState);
HashMap<String, String> hm = ex.getHashmap();
Log.v(TAG, "hm: " + hm);
答案 2 :(得分:1)
使用 this.getHashmap()代替ex.getHashmap()
public class Tradein extends Activity {
private static final String TAG = "Test";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.tradein);
//SoapTester ex = new SoapTester();
HashMap<String, String> hm = this.getHashmap();
Log.v(TAG, "hm: " + hm);//Getting Null Value here
}
}
答案 3 :(得分:0)
您可以直接在类初始化中填写地图:
public class SoapTester extends Activity {
private static final String TAG = "Test";
public static HashMap<String, String> map = new HashMap<String, String>() {
{
put("year", "Apple");
put("make", "Mango");
put("model", "Grape");
put("style", "Orange");
put("series", "Peach");
}
};
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
// No map initialization here
}
// etc.
}
答案 4 :(得分:0)
将Hashmap作为参数传递非常简单,只需要在Parent类的构造函数中初始化它。
儿童班:
HashMap<String, String> map = new HashMap<String, String>();;
map.put("OS", "Android");
Parent parent= new Parent();
parent.hashtest(map);
父类:
public class parent{
HashMap<String, String> map;
public Test() {
map= new HashMap<>();
}
public void hashtest(HashMap<String, String> map){
this.map=map;
Log.v("I fount it here", map.get("OS"));
}
}