按meet_id DESC排序

时间:2012-01-04 01:41:57

标签: php mysql sql-order-by

  

可能重复:
  Ambiguous column in INNER JOIN statement

我有一个表,其中使用内部联接sql语句从两个表中收集会议列表。我现在遇到一个问题,它是使用meeting_id primary(在会议桌中)按顺序降序排序的。外键(在房间表中)。

    <?php

$result = mysql_query("SELECT * FROM Meetings INNER JOIN Rooms ON Meetings.meeting_id = Rooms.meeting_id ORDER BY meeting_id")
or die(mysql_error());

if (mysql_num_rows($result) == 0) {
       echo '<h2>There Arent Any Meetings Setup Yet</h2>';
    } else {

while($info = mysql_fetch_array($result))
{

        echo "<tr>";
        echo "<td><br/>" .'Title: '. $info['title']." </td>";
        echo "<td><br/>" .'Chairman: '. $info['chairperson']. "</td>";
        echo "<td><br/>" .'Secretary: '. $info['secretary']."</td>";
        echo "<td><br/>" .'Terms Of Reference: '. $info['tof']. "</td>";
        echo "<td><br/>" .'Occurances: '. $info['occurances']. "</td>";
        echo "<td><br/>" .'Room: '. $info['room']. "</td>";
        echo "<td><br/>" .'Date: '. $info['date']. "</td>";
        echo "<td><br/>" .'Time: '. $info['time']. "</td>";
        echo "<hr>";
        }
    }
echo "</tr>";
echo "</table>";


?>

我收到以下错误消息:

'order'idate'id'在order order子句中是不明确的'

我的表格如下:

会议:meeting_id,职称,主席,秘书,出现

房间:room_id,房间,日期,时间,meeting_id

1 个答案:

答案 0 :(得分:2)

正如消息所说,这是模棱两可的; RoomsMessages都有meeting_id,而SQL不知道您已加入它们。只需指定一个或另一个:

$result =
    mysql_query("SELECT * FROM Meetings
                 INNER JOIN Rooms ON Meetings.meeting_id = Rooms.meeting_id
                 ORDER BY Rooms.meeting_id")