下面是我的代码,用于上传图像,然后创建一些包含其MySQL数据库的JSON。
<?php
ini_set('error_reporting', E_ALL);
//Get Libraries
require_once($_SERVER['DOCUMENT_ROOT'].'/Scripts/mobile_device_detect.php');
require_once($_SERVER['DOCUMENT_ROOT'].'/Scripts/WideImage/WideImage.php');
$Name = $_GET['name'];
$NumberImages = $_GET['numberImages'];
$FirstSetNumber = 1;
$SecondSetNumber = 2;
$uploading = $_POST['Uploading'];
if($uploading == "true")
{
$FirstSetNumber = $_POST['FirstSetNumber'];
$SecondSetNumber = $_POST['SecondSetNumber'];
$Name = $_POST['Name'];
$NumberImages = $_POST['NumberImages'];
echo "This is the set (".$FirstSetNumber."-".$SecondSetNumber.") for the Lighthouse (".$Name.") Which will consist of ".$NumberImages." pictures";
function connectToDatabase()
{
mysql_connect("host", "user", "password");
mysql_select_db("light_information") or die(mysql_error());
}
connectToDatabase();
$query = mysql_query('SELECT * FROM Lighthouses WHERE Name="'.$Name.'"') or die(mysql_error());
$PageType = mysql_result($query, 0, "PageType");
if($PageType = "englandtrinityhouse" || $PageType = "englandprivate" || $PageType = "scotlandnlb" || $PageType = "scotlandprivate")
{
$TypeFolder = "lighthouses";
}
$folderLocation = "../resources/images/".$TypeFolder."/".str_replace(" ", "-", $Name)."/";
if(!file_exists($folderLocation))
{
mkdir($folderLocation, 0777);
}
function findFileExtension($filename)
{
$filename = strtolower($filename) ;
$exts = split("[/\\.]", $filename) ;
$n = count($exts)-1;
$exts = $exts[$n];
return $exts;
}
//Thumbnail 1
$thumbnail1Extension = findFileExtension($_FILES['Thumbnail1']['name']);
$thumbnail1Name = str_replace(" ", "-", $name)."-Thumbnail-".$FirstSetNumber.".".$thumbnail1Extension;
$thumbnail1Location = $folderLocation.$thumbnail1Name;
$URLThumbnail1 = str_replace("../", "http://www.worldwidelighthouses.com/", $thumbnail1Location);
if(!move_uploaded_file($_FILES['Thumbnail1']['tmp_name'], $thumbnail1Location))
{
echo("Canny Move Thumbnail ".$FirstSetNumber);
}
//Thumbnail 2
$thumbnail2Extension = findFileExtension($_FILES['Thumbnail2']['name']);
$thumbnail2Name = str_replace(" ", "-", $name)."-Thumbnail-".$SecondSetNumber.".".$thumbnail2Extension;
$thumbnail2Location = $folderLocation.$thumbnail2Name;
$URLThumbnail2 = str_replace("../", "http://www.worldwidelighthouses.com/", $thumbnail2Location);
if(!move_uploaded_file($_FILES['Thumbnail2']['tmp_name'], $thumbnail2Location))
{
echo("Canny Move Thumbnail ".$SecondSetNumber);
}
//Large Image 1
$LargeImage1Extension = findFileExtension($_FILES['LargeImage1']['name']);
$LargeImage1Name = str_replace(" ", "-", $name)."-LargeImage-".$FirstSetNumber.".".$LargeImage1Extension;
$LargeImage1Location = $folderLocation.$LargeImage1Name;
$URLLargeImage1 = str_replace("../", "http://www.worldwidelighthouses.com/", $LargeImage1Location);
if(!move_uploaded_file($_FILES['LargeImage1']['tmp_name'], $LargeImage1Location))
{
echo("Canny Move Large ".$FirstSetNumber);
}
//Large Image 2
$LargeImage2Extension = findFileExtension($_FILES['LargeImage2']['name']);
$LargeImage2Name = str_replace(" ", "-", $name)."-LargeImage-".$SecondSetNumber.".".$LargeImage2Extension;
$LargeImage2Location = $folderLocation.$LargeImage2Name;
$URLLargeImage2 = str_replace("../", "http://www.worldwidelighthouses.com/", $LargeImage2Location);
if(!move_uploaded_file($_FILES['LargeImage2']['tmp_name'], $LargeImage2Location))
{
echo("Canny Move Large ".$SecondSetNumber);
}
$FirstSetNumber = $FirstSetNumber + 2;
$SecondSetNumber = $SecondSetNumber + 2;
$ThumbnailImagesJSONfromDB = mysql_result($query, 0, "SmallImages") or die(mysql_error());
$LargeImagesJSONfromDB = mysql_result($query, 0, "LargeImages") or die(mysql_error());
echo "Dis Far";
echo $ThumbnailImagesJSONfromDB;
// HTML to display data
?>
出于某种原因没有来自
的代码$ThumbnailImagesJSONfromDB = mysql_result($query, 0, "SmallImages") or die(mysql_error());
$LargeImagesJSONfromDB = mysql_result($query, 0, "LargeImages") or die(mysql_error());
echo "Dis Far";
echo $ThumbnailImagesJSONfromDB;`
向前工作。因此,我无法更新我的数据库,甚至无法检查数据库中已有的内容。可能导致此问题的任何想法? :)。只是为了澄清Echos的工作。
答案 0 :(得分:2)
很简单,mysql_result
如果给定行不存在传递的字段,则返回false
。第0行中不存在“SmallImages”或“LargeImages”,因为没有实际的SQL错误,die()
会输出空白消息。您应该确保您要查找的密钥确实存在于查询结果中。
既然问题已经满足,我必须建议您选择其他数据库API。阅读new PHP docs about choosing the right MySQL API。您使用的旧扩展程序已过时,不支持预准备语句或OOP,通常被认为不适合新项目。