我正在寻找一个将帧中的整数值转换为NTSC丢帧时间码(hh:mm:ss.ff)的函数。
我正在使用Delphi,但可以使用任何语言。
由于
答案 0 :(得分:4)
这个问题有一个众所周知的经典解决方案 ......
(当然,如果你知道你的价值范围有限,你可以使用较小的int类型)
const uint FRAMES_PER_10min = 10*60 * 30000/1001;
const uint FRAMES_PER_1min = 1*60 * 30000/1001;
const uint DISCREPANCY = (1*60 * 30) - FRAMES_PER_1min;
/** reverse the drop-frame calculation
* @param frameNr raw frame number in 30000/1001 = 29.97fps
* @return frame number using NTSC drop-frame encoding, nominally 30fps
*/
int64_t
calculate_drop_frame_number (int64_t frameNr)
{
// partition into 10 minute segments
lldiv_t tenMinFrames = lldiv (frameNr, FRAMES_PER_10min);
// ensure the drop-frame incidents happen at full minutes;
// at start of each 10-minute segment *no* drop incident happens,
// thus we need to correct discrepancy between nominal/real framerate once:
int64_t remainingMinutes = (tenMinFrames.rem - DISCREPANCY) / FRAMES_PER_1min;
int64_t dropIncidents = (10-1) * tenMinFrames.quot + remainingMinutes;
return frameNr + 2*dropIncidents;
} // perform "drop"
从生成的“drop”frameNumber中,您可以像往常一样使用标称的30fps帧速率计算组件......
frames = frameNumber % 30
seconds = (frameNumber / 30) % 60
依旧......
答案 1 :(得分:1)
function FramesToNTSCDropFrameCode(Frames:Integer;FramesPerSecond:Double):string;
var
iTH, iTM, iTS, iTF : word;
MinCount, MFrameCount : word;
begin
DivMod( Frames, Trunc(SecsPerMin * FramesPerSecond), MinCount, MFrameCount );
DivMod( MinCount, MinsPerHour, iTH, iTM );
DivMod( MFrameCount, Trunc(FramesPerSecond), ITS, ITF );
Result := Format('%.2d:%.2d:%.2d.%.2d',[iTH,iTM,iTS,iTF]);
end;
您需要从SysUtils单元复制DivMod例程,并在任何实现此功能的过程中包含sysUtils单元。