Question

我正在使用我在之前项目中使用的旧脚本来上传图像。该项目仅使用HTML和PHP使上传更易于处理！：）

我是Jquery和Ajax处理程序的新手，由于我目前的项目高度使用处理程序，我需要上传内容而不刷新整个页面，也许只是一个div。

我的剧本：

 function postfile() {
var filename = $("#image").val();
      $.ajax({
          type: "POST",
          url: "pages/minutes1.php",
          secureuri:false,
      fileElementId:'image',
          enctype: 'multipart/form-data',
          data: "submit=yes&image=" + {file: filename},
           success: function(msg5){
                $("#upform").html(msg5);
           }
      });
}

我的PHP和HTML：

    <?
/**
* The following uploader was not originally suited for text based files<br>
* Copied and Re-used from previous projects<br>
*/
$submit = $_POST['submit'];
 if($submit=="yes") 
 {
//define a maxim size for the uploaded images in Kb
 define ("MAX_SIZE","100"); 

//This function reads the extension of the file. It is used to determine if the file  is an image by checking the extension.
 function getExtension($str) {
         $i = strrpos($str,".");
         if (!$i) { return ""; }
         $l = strlen($str) - $i;
         $ext = substr($str,$i+1,$l);
         return $ext;
 }

//This variable is used as a flag. The value is initialized with 0 (meaning no error  found)  
//and it will be changed to 1 if an error occurs.  
//If the error occurs the file will not be uploaded.
 $errors=0;
//checks if the form has been submitted
    //reads the name of the file the user submitted for uploading
    $image=$_FILES['image']['name'];
if(!$image){
?>
<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td class="tabcol1 font1" style="text-align: center;">
There was no minutes file attached!
</td></tr>
<tr>
<td class="tabcol4 font1" style="text-align: center;">
Please wait as you are directed back
</td></tr>
</table>
<?
}elseif($image) 
    {
    //get the original name of the file from the clients machine
        $filename = stripslashes($_FILES['image']['name']);
    //get the extension of the file in a lower case format
        $extension = getExtension($filename);
        $extension = strtolower($extension);
    //if it is not a known extension, we will suppose it is an error and will not  upload the file,  
    //otherwise we will do more tests
 if (($extension != "doc") && ($extension != "txt")  && ($extension != "pdf") && ($extension != "odt") && ($extension != "docx") && ($extension != "rtf")) 
        {
?>
<b>The file type uploaded is not supported!</b><br><br>

<b>Supported formats:</b> doc, docx, pdf, odt, txt, rtf
<?
}
        else
        {
//get the size of the image in bytes
 //$_FILES['image']['tmp_name'] is the temporary filename of the file
 //in which the uploaded file was stored on the server
 $size=filesize($_FILES['image']['tmp_name']);

//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
?>
File size, too large! (if you need lieniency please contact webmaster)
<?
}else{
//we will give an unique name, for example the time in unix time format
$exam = substr("$filename", 0, -2);
function MakeRandom($minLength, $lastNr){

   $i = 0;
   while ($i <= $minLength){
      $randomnr = ($i === $minLength) ? 1 : rand(0, 9);
      $strNumber = (!$strNumber) ? $strNumber = $randomnr : $strNumber .= $randomnr;
      $i++;
   }

   return $strNumber;
}

// show the number
$num = MakeRandom(5, 1);
$col = "$exam$num";
$image_name = $col.'.'.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname="minutes/".$image_name;
//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES['image']['tmp_name'], $newname);
if (!$copied){
?>
File uploaded and E-mail sent!
<?
}
}
}
}
}else{
?>
<div id="upform">
<form method="post">
<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td class="font1 tabcol1">
<!-- begin 2 column table -->
<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td class="font1">
&nbsp;<b>Choose a file to upload:<br> <input id="image" name="image" type="file" /><br />
<input type="button" id="submit" name="submit" value="submit" onclick="postfile()">
</td>
<td class="font1"></td>
</tr>
</table>
<!-- End 2 column table -->
</td></tr>
</table>
</form>
</div>
<?
}
?>

我得到的问题是，即使我添加了一个文件并按下提交，

它给了我没有图像错误。

我相信我写的脚本错了，但我找不到任何语法错误。

所有帮助将不胜感激！

提前谢谢你：）

Answer 1

$ .ajax不支持文件上传，与普通表单提交的方式相同。解决此问题的通常建议是将上传脚本嵌入到iframe中，以便在上传时不会重新加载页面。

这是一个example。

PHP＆amp; Jquery图像上传 - 没有文件问题

1 个答案: