Question

有人知道如何将GPS度转换为十进制值，反之亦然吗？

我必须开发一种方式，用户可以插入地址并获取GPS值（程度和/或小数），但我需要知道的主要是如何转换值，导致用户也可以插入GPS值（度或小数）。因为我需要从谷歌地图获取地图，这需要十进制。

我尝试了一些代码，但我得到了大数字...就像这个：

function ConvertDMSToDD(days, minutes, seconds, direction) {
    var dd = days + minutes/60 + seconds/(60*60);
    //alert(dd);
    if (direction == "S" || direction == "W") {
        dd = '-' + dd;
    } // Don't do anything for N or E
    return dd;
}

任何人？

谢谢。

Answer 1

首先感谢@Eugen Rieck的帮助。这是我的最终代码，希望它可以帮助某人：

度到小数

function getDMS2DD(days, minutes, seconds, direction) {
    direction.toUpperCase();
    var dd = days + minutes/60 + seconds/(60*60);
    //alert(dd);
    if (direction == "S" || direction == "W") {
        dd = dd*-1;
    } // Don't do anything for N or E
    return dd;
}

根据此link

，

十进制到度

function getDD2DMS(dms, type){

    var sign = 1, Abs=0;
    var days, minutes, secounds, direction;

    if(dms < 0)  { sign = -1; }
    Abs = Math.abs( Math.round(dms * 1000000.));
    //Math.round is used to eliminate the small error caused by rounding in the computer:
    //e.g. 0.2 is not the same as 0.20000000000284
    //Error checks
    if(type == "lat" && Abs > (90 * 1000000)){
        //alert(" Degrees Latitude must be in the range of -90. to 90. ");
        return false;
    } else if(type == "lon" && Abs > (180 * 1000000)){
        //alert(" Degrees Longitude must be in the range of -180 to 180. ");
        return false;
    }

    days = Math.floor(Abs / 1000000);
    minutes = Math.floor(((Abs/1000000) - days) * 60);
    secounds = ( Math.floor((( ((Abs/1000000) - days) * 60) - minutes) * 100000) *60/100000 ).toFixed();
    days = days * sign;
    if(type == 'lat') direction = days<0 ? 'S' : 'N';
    if(type == 'lon') direction = days<0 ? 'W' : 'E';
    //else return value     
    return (days * sign) + 'º ' + minutes + "' " + secounds + "'' " + direction;
}
alert(getDD2DMS(-8.68388888888889, 'lon'));

`

Answer 2

经过一段时间后，无法使上面的脚本正常工作；只需将dms赋予函数

function ConvertDMSToDEG(dms) {   
    var dms_Array = dms.split(/[^\d\w\.]+/); 
    var degrees = dms_Array[0];
    var minutes = dms_Array[1];
    var seconds = dms_Array[2];
    var direction = dms_Array[3];

    var deg = (Number(degrees) + Number(minutes)/60 + Number(seconds)/3600).toFixed(6);

    if (direction == "S" || direction == "W") {
        deg = deg * -1;
    } // Don't do anything for N or E
    return deg;
}

反之亦然，只是给出脚本的度数，纬度（纬度）为假

function ConvertDEGToDMS(deg, lat) {
    var absolute = Math.abs(deg);

    var degrees = Math.floor(absolute);
    var minutesNotTruncated = (absolute - degrees) * 60;
    var minutes = Math.floor(minutesNotTruncated);
    var seconds = ((minutesNotTruncated - minutes) * 60).toFixed(2);

    if (lat) {
        var direction = deg >= 0 ? "N" : "S";
    } else {
        var direction = deg >= 0 ? "E" : "W";
    }

    return degrees + "°" + minutes + "'" + seconds + "\"" + direction;
}

希望这对人们有帮助。

如何在jquery或javascript和PHP中将GPS度转换为十进制，反之亦然？

2 个答案: