Django模型错误 - “TypeError：'xxx'是此函数的无效关键字参数

Question

我收到错误：

TypeError: 'person' is an invalid keyword argument for this function

我的模特是：

class Investment(models.Model):
company = models.ManyToManyField("Company", related_name ="Investments_company")
financial_org = models.ManyToManyField("Financial_org", related_name ="Investments_financial_org")
person = models.ManyToManyField("Person", related_name ="Investments_person")

我的测试（给出错误）：

investment1 = Investment(company = [], financial_org = financial1, person = [])

Answer 1

1. 在没有多少人的情况下实施您的模型，investment1 = Investment()

2. 保存模型，investment1.save()

3. 添加多对，investment1.person.add(person_model)或investment1.person.create(name='foo')

等several ways to do it

在保存模型之前，您可能不会使用ManyToMany关系，这是因为ManyToMany关系表中的行需要关系两侧的模型的pk。