Question

刚开始使用Django TastyPie来使用JSON公开数据。尝试使用tastypie.Api为urls.py

绑定资源

给出的例子 http://django-tastypie.readthedocs.org/en/latest/tutorial.html#creating-resources 不开箱即用。

我的urls.py条目：

#now for the api
from tserver.api import PurchaseResource,DataResource

#combine several APIs
from tastypie.api import Api

api = Api(api_name='')
api.register(PurchaseResource(),canonical=True)
api.register(DataResource(),canonical=True)

urlpatterns = patterns('', (r'^api/',include(api.urls)),
                      )

和api.py：

#!/bin/env python

from tastypie.resources import ModelResource
from tastypie import fields
from tserver.models import Purchase,Data

class DataResource(ModelResource):
    class Meta:
        queryset = Data.objects.all()


class PurchaseResource(ModelResource):
    Info = fields.ForeignKey(DataResource,'data')
    class Meta:
        queryset = Purchase.objects.all()
        resource_name = 'purchase'

和models.py：

class Data(models.Model):
    tagID    = models.CharField(max_length=40)
    dtime    = models.DateTimeField()
    vcardf   = models.CharField(max_length = 600)


class Purchase(models.Model):
    Info        = models.ForeignKey('Data',unique=True)
    payment_method = models.CharField(max_length=20,choices=PAYMENT_METHOD)
    TotalAmount    = models.DecimalField(max_digits = 20, decimal_places=2)
    TotalDiscount  = models.DecimalField(max_digits = 20, decimal_places=2)
    valid_upto     = models.DateTimeField()

最后当我试一试时，错误：

http://localhost:8000/api/data/1/?format=json

结果：

Page not found (404)
Request Method:     GET
Request URL:    http://localhost:8000/api/data/1/?format=json

Using the URLconf Django tried these URL patterns, in this order:

^admin/
^(?P<api_name>)/$ [name='api__top_level']
^(?P<api_name>)/
^(?P<api_name>)/

The current URL, api/data/1/, didn't match any of these.

但如果我只是在urls.py使用

，那么这个问题就不存在了

urlpatterns = patterns('', (r'^api/',include(DataResoure().urls)),
                       )

当我们尝试将api.register(...)与<{1}}结合在一起时会出现什么问题？

Answer 1

我们总是指定api_name和资源名称。像

注册文件

public_api = Api(api_name='public')
public_api.register(BookingPostResource())
public_api.register(SearchResource())

private_api = Api(api_name='private')
private_api.register(BookingPostResource())
private_api.register(SearchResource())

urls.py

urlpatterns = patterns('',
    url(r'^api/', include(public_api.urls)),
    url(r'^api/', include(private_api.urls)),
)

我们得到网址：

http://www.mysite.com/api/public/ {RESOURCE_NAME}

http://www.mysite.com/api/private/ {RESOURCE_NAME}

我想警告你，tastypie表现出非常糟糕的生产力，并且包含一些可能导致数据丢失的严重问题，我们在它开始工作之前做了很多猴子修补。目前我们正在转向我们自己的框架。我强烈建议你使用像活塞一样小的东西，但它也不是银弹。

tastypie注册问题

1 个答案: