Question

我有这个查询来计算一个类别中的项目数：

SELECT category, COUNT(*) AS category_count FROM users GROUP BY category

这会产生如下结果：

category   category_count
========== ================
X          3
Y          2

现在，在PHP中我想显示类别的计数。例如，我可能想要回应X类中的计数，我该怎么做？

提前致谢

Answer 1

假设$result包含您的查询结果：

while ($row = mysql_fetch_array($result))
{
    echo 'Category: ' . $row['category'];
    if ($row['category'] == 'X')
    {
       echo  ' Count: ' . $row['category_count'];
    }
    echo '<br/>';
}

Answer 2

$res = mysql_query("SELECT category, COUNT(*) AS category_count FROM users GROUP BY category");
while($row = mysql_fetch_assoc($res)){
   echo $row['category'].": ".$row['category_count']."<br/>";
}

Answer 3

$result = mysql_query("SELECT category, COUNT(*) AS category_count FROM users GROUP BY     category");

while ($row = mysql_fetch_array($result, MYSQL_NUM)) {
{
   if ( $row['category'] == 'x' )
   {
      echo $row['category_count'];
   }
}

Answer 4

while ($row = mysql_fetch_array($result))
{
    echo 'Category: ' . $row['category'] . ' Count:' . $row['category_count'];
    echo "<br>";
}

Answer 5

$conn = mysql_connect("address","login","pas s");
mysql_select_db("database", $conn);

$Var = mysql_query("query");

While ($row = mysql_fetch_assoc($var) {   echo $var["column"] }.

Answer 6

如果在查询中使用where子句会更好。

SELECT COUNT(*) AS category_count FROM users WHERE category = 'x'

PHP MySQL显示计数

6 个答案: