任何人都可以共享示例代码,以便在启动/启动设备时启动Android应用程序吗?
答案 0 :(得分:1)
此代码将在启动时启动应用程序。你需要听ACTION_BOOT_COMPLETE。
in AndroidManifest.xml (application-part):
<receiver android:enabled="true" android:name=".BootUpReceiver"
android:permission="android.permission.RECEIVE_BOOT_COMPLETED">
<intent-filter>
<action android:name="android.intent.action.BOOT_COMPLETED" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</receiver>
[..]
<uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
[..]
public class BootUpReceiver extends BroadcastReceiver{
@Override
public void onReceive(Context context, Intent intent) {
Intent i = new Intent(context, MyActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
}