Question

可能重复：
Symfony2 AJAX Login

我已经实现了一个自定义身份验证处理程序服务来处理AJAX登录请求，如下所示：https://stackoverflow.com/a/8312188/267705

但是我该如何处理正常的登录请求？调用默认行为会很好，但我不知道怎么做也没找到。

Answer 1

这是实现目标的方法之一：

namespace YourVendor\UserBundle\Handler;

// "use" statements here

class AuthenticationHandler
implements AuthenticationSuccessHandlerInterface,
           AuthenticationFailureHandlerInterface
{
    private $router;

    public function __construct(Router $router)
    {
        $this->router = $router;
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token)
    {
        if ($request->isXmlHttpRequest()) {
            // Handle XHR here
        } else {
            // If the user tried to access a protected resource and was forces to login
            // redirect him back to that resource
            if ($targetPath = $request->getSession()->get('_security.target_path')) {
                $url = $targetPath;
            } else {
                // Otherwise, redirect him to wherever you want
                $url = $this->router->generate('user_view', array(
                    'nickname' => $token->getUser()->getNickname()
                ));
            }

            return new RedirectResponse($url);
        }
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        if ($request->isXmlHttpRequest()) {
            // Handle XHR here
        } else {
            // Create a flash message with the authentication error message
            $request->getSession()->setFlash('error', $exception->getMessage());
            $url = $this->router->generate('user_login');

            return new RedirectResponse($url);
        }
    }
}

享受。 ;）

从自定义身份验证处理程序调用默认处理程序

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