如何在Hibernate 3.0中实现mysql date_sub()函数

时间:2011-12-27 20:07:25

标签: hibernate

您好我必须在hibernate中编写一个查询

SELECT * FROM `tablename` where created_at> DATE_SUB(curdate(),INTERVAL 7 DAY) 

在hibernate中。我已经发布了有关此主题的查询。但没有人帮助我。在hiberanate中可以写这样的查询吗?请回复。

3 个答案:

答案 0 :(得分:8)

您可以使用native SQL query

String sql = "SELECT * FROM tablename WHERE created_at > DATE_SUB(curdate(), INTERVAL 7 DAY)"
Query query = session.createSQLQuery(sql);
List result = query.list();

或者您可以使用Hibernate Criteria Restrictions.sqlRestriction

String sqlWhere = "{alias}.created_at > DATE_SUB(curdate(), INTERVAL 7 DAY)";
Criteria criteria = session.createCriteria(MyEntity.class);
criteria.add(Restrictions.sqlRestriction(sqlWhere));
List result = criteria.list();

希望有所帮助。

答案 1 :(得分:2)

你也可以扩展hibernate的mysql Dialect来支持date_add函数。

public class CommonMySQL5InnoDBDialect extends MySQL5InnoDBDialect {
    public CommonMySQL5InnoDBDialect() {
        super();
        //mysql date_add function support.
        registerFunction( "date_add_interval", new SQLFunctionTemplate( DateType.INSTANCE, "date_add(?1, INTERVAL ?2 ?3)" ) );
    }
}

然后你可以在你的HQL中使用注册的函数。

from tablename where created_at > date_add_interval(curdate(), 7  DAY)

答案 2 :(得分:0)

String sql1 = "select  uh.ServiceDate from tablename  uh WHERE uh.ServiceDate >= DATE_SUB(curdate(), INTERVAL 1 YEAR)";

Query query1 = session.createSQLQuery(sql1);

 List result = query1.list();

         use this list in HQL

String queryString = "delete  from tablename  u  where  u.serviceDate in (:result)";
query =session.createQuery(queryString);
query.setParameterList("result", result);