我正在使用pyes用法示例here
我正在使用四个文档索引 test-index ,稍后使用不同的偏移量进行查询。 start 参数不会改变我的偏移量,无论其值如何,我都会得到相同的结果。为什么会这样?
from pyes import *
conn = ES(["localhost:9200"])
try:
conn.delete_index('test-index')
except:
pass
conn.create_index('test-index')
mapping = {u'name': {'boost': 1.0,
'index': 'analyzed',
'store': 'yes',
'type': u'string',
"term_vector" : "with_positions_offsets"},
u'title': {'boost': 1.0,
'index': 'analyzed',
'store': 'yes',
'type': u'string',
"term_vector" : "with_positions_offsets"},
u'pos': {'store': 'yes',
'type': u'integer'},
u'uuid': {'boost': 1.0,
'index': 'not_analyzed',
'store': 'yes',
'type': u'string'}}
conn.put_mapping("test-type", {'properties':mapping}, ["test-index"])
conn.index({"name":"Joe Tester", "uuid":"11111", "position":1}, "test-index", "test-type", 1)
conn.index({"name":"Bill Baloney", "uuid":"22222", "position":2}, "test-index", "test-type", 2)
conn.index({"name":"Joe Joseph", "uuid":"33333", "position":3}, "test-index", "test-type", 3)
conn.index({"name":"Last Joe", "uuid":"44444", "position":4}, "test-index", "test-type", 4)
conn.refresh(["test-index"])
q = TermQuery("name", "joe")
r0 = conn.search(q, indices = ["test-index"], start=0, size=1)
r1 = conn.search(q, indices = ["test-index"], start=1, size=1)
r2 = conn.search(q, indices = ["test-index"], start=2, size=1)
print('0: {0}'.format(r0['hits']['hits']))
print('1: {0}'.format(r1['hits']['hits']))
print('2: {0}'.format(r2['hits']['hits']))
输出:
$ python pagination.py
0: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
1: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
2: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
我的pyes版本是0.16.0
答案 0 :(得分:4)
问题在于如何将请求发送到ES,尽管我仍然不清楚它失败的原因。
而不是像我原来那样直接向ES发送查询:
r0 = conn.search(q, indexes = ["test-index"], start=0, size=1)
r1 = conn.search(q, indexes = ["test-index"], start=1, size=1)
r2 = conn.search(q, indexes = ["test-index"], start=2, size=1)
我将查询包装在pyes.query.Search对象中:
r0 = conn.search(Search(q, start=0, size=1), indexes = ["test-index"])
r1 = conn.search(Search(q, start=1, size=1), indexes = ["test-index"])
r2 = conn.search(Search(q, start=2, size=1), indexes = ["test-index"])
有效,请参阅下面的输出:
0s: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'4', u'_source': {u'position': 4, u'name': u'Last Joe', u'uuid': u'44444'}, u'_index': u'test-index'}]
1s: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'1', u'_source': {u'position': 1, u'name': u'Joe Tester', u'uuid': u'11111'}, u'_index': u'test-index'}]
2s: [{u'_score': 0.19178301, u'_type': u'test-type', u'_id': u'3', u'_source': {u'position': 3, u'name': u'Joe Joseph', u'uuid': u'33333'}, u'_index': u'test-index'}]
答案 1 :(得分:2)
确保您使用的搜索类型为Query then Fetch。