通过url模式调用JSP文件时的空白页面

时间:2011-12-26 23:44:20

标签: jsp servlets model-view-controller

使用Netbeans我在localhost上设置了一个基于MVC的网站。我将控制器设置为servlet,将客户端请求指向相关的JSP页面。

当我尝试直接访问JSP文件时,我没有任何问题,但是当我尝试通过控制器servlet中设置的url模式时,我得到了空白页面。我知道指向正在工作,因为如果我请求一个尚未在控制器servlet中命名的url模式,我会收到404 not found错误。

以下是servlet模板文件的代码:

 public class ControllerServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
    String userPath = request.getServletPath();
    if (userPath.equals("/book")) {   
    }
    String url = "/WEB-INF" + userPath + ".jsp";
    request.getRequestDispatcher(url).forward(request, response);
}


@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {

    String userPath = request.getServletPath();
    if (userPath.equals("/profile")) {
    } else if (userPath.equals("/updates")) {
    } else if (userPath.equals("/mybooks")) {
    }
    String url = "/WEB-INF/view" + userPath + ".jsp";
    request.getRequestDispatcher(url).forward(request, response);
}

 }

ControllerServlet文件在标准HTTPServlet代码之上包含一个额外的行:

@WebServlet(name = "ControllerServlet", loadOnStartup = 1, urlPatterns = {"/profile", "/mybooks", "/updates", "/book"})

XML文件:

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">

<context-param>
    <param-name>javax.faces.PROJECT_STAGE</param-name>
    <param-value>Development</param-value>
</context-param>
<context-param>
    <description>The relative path to images of book covers.</description>
    <param-name>coversImagePath</param-name>
    <param-value>img/bookCovers</param-value>
</context-param>
<servlet>
    <servlet-name>Faces Servlet</servlet-name>
    <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
    <load-on-startup>0</load-on-startup>
</servlet>
<servlet>
    <servlet-name>action</servlet-name>
    <servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
    <init-param>
        <param-name>config</param-name>
        <param-value>/WEB-INF/struts-config.xml</param-value>
    </init-param>
    <init-param>
        <param-name>debug</param-name>
        <param-value>2</param-value>
    </init-param>
    <init-param>
        <param-name>detail</param-name>
        <param-value>2</param-value>
    </init-param>
    <load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>Faces Servlet</servlet-name>
    <url-pattern>/faces/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
    <servlet-name>action</servlet-name>
    <url-pattern>*.do</url-pattern>
</servlet-mapping>
<session-config>
    <session-timeout>
        30
    </session-timeout>
</session-config>
<welcome-file-list>
    <welcome-file>index.xhtml</welcome-file>
</welcome-file-list>
<jsp-config>
    <jsp-property-group>
        <description>header and footer settings</description>
        <url-pattern>/index.jsp</url-pattern>
        <url-pattern>/WEB-INF/view/*</url-pattern>
        <url-pattern>/book.jsp</url-pattern>
        <include-prelude>/WEB-INF/jspf/header.jspf</include-prelude>
        <include-coda>/WEB-INF/jspf/footer.jspf</include-coda>
    </jsp-property-group>
</jsp-config>
<resource-ref>
    <description>Connects to database for bookshelves application.</description>
    <res-ref-name>jdbc/bookshelves</res-ref-name>
    <res-type>javax.sql.DataSource</res-type>
    <res-auth>Container</res-auth>
    <res-sharing-scope>Shareable</res-sharing-scope>
</resource-ref>
</web-app>

1 个答案:

答案 0 :(得分:0)

将JSP放在/WEB-INF文件夹中。它将修复两件事:

  1. 您不会得到空白页。
  2. 您将无法直接访问JSP(这是正确的行为!)
  3. 您需要修复与问题无直接关系的其他2个问题:

    1. 除非您知道自己在做什么,否则永远不要压制异常。删除try-catch
    2. 永远不要忽略服务器日志。 forward()确实抛出异常。
    3. 额外的好处是你不会再得到一个空白页面,因此会立即看到你自己解释异常的错误(只有当你没有通过某些自定义覆盖服务器默认HTTP 500错误页面时) {1}}反过来没有显示异常的任何内容。)