Question

我试图进行http - post call。我发给他这个请求的服务器需要有两个参数
1.第一个参数是Int 2.第二个参数是我作为字符串发送的枚举

我尝试以两种方式做到这两种方式都失败了：

第一种方式：

 List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);  
 nameValuePairs.add(new BasicNameValuePair("intVal", "-100")); 
 nameValuePairs.add(new BasicNameValuePair("enumVal", "enumAsString"));  
 httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

我得到'酒吧请求'作为回应。

第二种方式：

      DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(SERVER_ADDRESS + METHOD_NAME);
try
{
     HttpParams postParams = new BasicHttpParams();
           postParams.setIntParameter("intVal", -100 ); 
           postParams.setParameter   ("enumVal" , "enumAsString" ); 

           httppost.setParams(postParams);

           HttpResponse p = httpclient.execute(httppost);
      }
      catch(Exception e) 
      {

                  .... 

      }

通过这种方式，我看到服务器获取参数 - 但第一个参数（需要为int）为0，第二个参数（需要为枚举）也为0。

P.S：在服务器上运行的代码是WCF代码 - 使用REST。

请..我必须解决这个问题...

感谢。

Answer 1

这适用于我的情况。试试这个，让我知道发生了什么......

List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>();
nameValuePair.add(new BasicNameValuePair("uname","test"));
nameValuePair.add(new BasicNameValuePair("pws","test"));
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);  
httppost.addHeader("Content-Type", "application/x-www-form-urlencoded");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs,HTTP.UTF_8));

// Execute HTTP Post Request  
HttpResponse response = httpclient.execute(httppost);

Answer 2

使用Andorid，您可以使用HttpPost和HttpUrlConnection两种方式发送参数：

第一种方式：

HttpClient httpclient;
HttpPost httppost;
ArrayList<NameValuePair> postParameters;
httpclient = new DefaultHttpClient();
httppost = new HttpPost("your login link");


postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("param1", "param1_value"));
postParameters.add(new BasicNameValuePair("param2", "param2_value"));

httppost.setEntity(new UrlEncodedFormEntity(postParameters));

HttpResponse response = httpclient.execute(httppost);

第二种方式是：

        String charset = "UTF-8";
    String query = String.format("debug_data=%s&"
                            + "client_auth_hash=%s&" 
                            + "timestamp=%s&"
                            + "client_api_ver=%s&",
                            URLEncoder.encode("1", charset),
                            URLEncoder.encode(hash, charset),
                            URLEncoder.encode(timeStamp, charset),
                            URLEncoder.encode(clientApiVersion, charset));

        System.setProperty("http.keepAlive", "false");
        HttpURLConnection connection = (HttpURLConnection) new URL(url).openConnection();
        connection.setDoOutput(true);
        connection.setConnectTimeout(5000); //miliseconds
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Charset", charset);
        connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded;charset=" + charset);
        OutputStream output = null;
        try {
            output = connection.getOutputStream();
            output.write(query.getBytes(charset));
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (output != null)
                try {
                    output.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
        }

        int status = ((HttpURLConnection) connection).getResponseCode();
        Log.d("", "Status : " + status);

        for (Entry<String, List<String>> header : connection
                .getHeaderFields().entrySet()) {
            Log.d("Headers",
                    "Headers : " + header.getKey() + "="
                            + header.getValue());
        }

        InputStream response = new BufferedInputStream(connection.getInputStream());

        int bytesRead = -1;
        byte[] buffer = new byte[30 * 1024];
        while ((bytesRead = response.read(buffer)) > 0) {
        //read the response in pieces if it's needed
            byte[] buffer2 = new byte[bytesRead];
        }
        connection.disconnect();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }

两种方式都正常运作。

Answer 3

好吧，没有什么可以从战斗的方式但这是我解决这个问题及其工作正常的方式

 JSONObject json = new JSONObject();
 json.put("intVal", -100);
 json.put("enumVal", enumAsString);


 StringEntity t = new StringEntity(json.toString(), "UTF-8");

 httppost.setEntity(t);


 httppost.setHeader("Accept", "application/json");
 httppost.setHeader("Content-type", "application/json");

无法在http post请求中发送两个参数

3 个答案: