Question

这段代码是python上一本书的示例代码。这是一个输入整数并显示整数的总和，总数和平均值的简单程序。但是，当我尝试运行代码时，我在第18行收到语法错误，即冒号。这段代码对我来说非常好。有什么想法吗？

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: "
    if line:
        try:
            number = int(line)
        except ValueError as err:
            print(err)
            continue
    total += number
    count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

当我尝试运行时，我收到错误：

  File "./intproj.py", line 18
    else:
       ^
SyntaxError: invalid syntax

我在Ubuntu 11.10上使用IDLE作为IDE使用python 3.2.2

更新代码：

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: ")
    if line:
        try:
            number = int(line)
        except ValueError as err:
                print(err)
                continue
    total += number
    count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

现在得到错误：

  File "./intproj.py", line 18
    else:
       ^
SyntaxError: invalid syntax

固定代码：

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: ")
    if line:
        try:
            number = int(line)
        except ValueError as err:
                print(err)
                continue
        total += number
        count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

谢谢！

Answer 1

第9行似乎缺少)

变化：

line = input("integer: "

到

line = input("integer: ")

except行需要缩进以匹配try

和行：

total += number
count += 1

也需要缩进，否则if和else语句不会排列。即代码应该是这样的：

print("type integers, each followed by Enter; or just Enter to finish")

total = 0
count = 0

while True:
    line = input("integer: ")
    if line:
        try:
            number = int(line)
        except ValueError as err:
            print(err)
            continue
        total += number
        count += 1
    else:
        break
if count:
    print("count=", count, "total =", total, "mean =", total / count)

Answer 2

您忘记关闭上一行的input()来电。

Answer 3

你需要一个结束括号：

line = input("integer: ")

Answer 4

除了右括号问题之外，显示except ValueError as err:的行没有足够的缩进（其缩进级别应与try语句的缩进级别匹配）。这应修复上面提到的第18行else错误。

Answer 5

以total +=和count +=开头的行需要以八个空格而不是四个空格开头。

简单的Python 3.2.2程序中的语法错误

5 个答案: