我必须在mysql中比较日期,例如:
select col1,col2 from table where date <= '2011-12-24' (present date)
但是这会使所有日期的输出仅低于“2011-12-24”。
答案 0 :(得分:4)
我怀疑您的问题是您的date
列是时间戳,但您将其与日期进行比较。完成此操作后,您的2011-12-24
会转换为2011-12-24 00:00:00.0000
,因此任何具有合理时间2011-12-24
的内容都会在此之后。在你的情况下,我会使用
select col1,col2 from table where my_date < '2011-12-25' (present date + 1 day)
或者,如果您坚持使用<=
,那么
select col1,col2 from table where date(my_date) <= '2011-12-24' (present date)
答案 1 :(得分:0)
好吧,现在尝试以下方法。
SELECT col1,col2 FROM table
WHERE date <= STR_TO_DATE('2011-12-24 00:00:00', '%Y-%m-%d %H:%i:%s');
如果您需要在比较中使用TimeStamp部分,这将更好地帮助您。
STR_TO_DATE(str,format)
是DATE_FORMAT()
函数的反函数。
STR_TO_DATE()
会返回DATETIME
值。
格式字符串中可以使用以下说明符。
格式说明符字符前需要'%'字符。
Specifier Description
%a Abbreviated weekday name (Sun..Sat)
%b Abbreviated month name (Jan..Dec)
%c Month, numeric (0..12)
%D Day of the month with English suffix (0th, 1st, 2nd, 3rd, ?-)
%d Day of the month, numeric (00..31)
%e Day of the month, numeric (0..31)
%f Microseconds (000000..999999)
%H Hour (00..23)
%h Hour (01..12)
%I Hour (01..12)
%i Minutes, numeric (00..59)
%j Day of year (001..366)
%k Hour (0..23)
%l Hour (1..12)
%M Month name (January..December)
%m Month, numeric (00..12)
%p AM or PM
%r Time, 12-hour (hh:mm:ss followed by AM or PM)
%S Seconds (00..59)
%s Seconds (00..59)
%T Time, 24-hour (hh:mm:ss)
%U Week (00..53), where Sunday is the first day of the week
%u Week (00..53), where Monday is the first day of the week
%V Week (01..53), where Sunday is the first day of the week; used with %X
%v Week (01..53), where Monday is the first day of the week; used with %x
%W Weekday name (Sunday..Saturday)
%w Day of the week (0=Sunday..6=Saturday)
%X Year for the week where Sunday is the first day of the week, numeric, four digits; used with %V
%x Year for the week, where Monday is the first day of the week, numeric, four digits; used with %v
%Y Year, numeric, four digits
%y Year, numeric (two digits)
%% A literal '%' character
%x x, for any 'x' not listed above
答案 2 :(得分:0)
这有效... jst需要将列转换为日期格式 选择表格中的col1,col2,其中DATE_FORMAT(日期,'%Y%m%d')&lt; =''2011-12-24'