如何在TimePicker Android中以30分钟的间隔设置开始时间和结束时间?

时间:2011-12-24 06:13:44

标签: android

我正在使用android中的DatePicker和TimePicker。我从服务器获得开始时间和时间。我可以使用this link

以编程方式设置最大日期和分钟日期

我想在时间戳中设置最短时间(07:00)和最长时间(10:00)并保持30分钟的间隔。我尝试使用This Link

我需要的是在最小07:00和最长时间= 10:00和间隔时间设置时间表 07:00,07:30,08:00等。

这是相同的代码`

  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    TimePicker pn = (TimePicker) findViewById(R.id.tp_powernap);

    pn.setCurrentHour(7);
    pn.setCurrentMinute(0);
    System.out.println("timepicker erstellt");
    pn.setDescendantFocusability(TimePicker.FOCUS_BLOCK_DESCENDANTS);
    System.out.println("Tastatur geblockt");
    pn.setOnTimeChangedListener(StartTimeChangedListener);
    System.out.println("starttimechangedlistener");
    pn.setIs24HourView(false);
}


private TimePicker.OnTimeChangedListener StartTimeChangedListener =
    new TimePicker.OnTimeChangedListener() {

    public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {
        updateDisplay(view, hourOfDay, minute);          
    }
};

private TimePicker.OnTimeChangedListener NullTimeChangedListener =
    new TimePicker.OnTimeChangedListener() {

    public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {

    }
};



private void updateDisplay(TimePicker timePicker, int hourOfDay, int minute) {
    int nextMinute = 0;
    timePicker.setOnTimeChangedListener(NullTimeChangedListener);
    if (minute >= 45 && minute <= 59) 
        nextMinute = 45;  
    else if (minute  >= 30) 
        nextMinute = 30;
    else if (minute >= 15) 
        nextMinute = 15;
    else if (minute > 0) 
        nextMinute = 0; 
    else { 
        nextMinute = 45; 
    }

    if (minute - nextMinute == 1) {
        if (minute >= 45 && minute <= 59) 
            nextMinute = 00; 
        else if(minute  >= 30) 
            nextMinute = 45;
        else if(minute >= 15) 
            nextMinute = 30;
        else if(minute > 0) 
            nextMinute = 15; 
        else { 
            nextMinute = 15; 
        }
    }

    timePicker.setCurrentMinute(nextMinute);

    timePicker.setOnTimeChangedListener(StartTimeChangedListener);

}

1 个答案:

答案 0 :(得分:0)

仅供参考(这是一个老问题)。可以使用以下hack来实现间隔:

Class<?> classForid = Class.forName("com.android.internal.R$id");
Field field = classForid.getField("minute");

NumberPicker mMinuteSpinner = (NumberPicker) timePicker
                    .findViewById(field.getInt(null));
mMinuteSpinner.setMinValue(0);
mMinuteSpinner.setMaxValue((60 / TIME_PICKER_INTERVAL) - 1);
List<String> displayedValues = new ArrayList<String>();
for (int i = 0; i < 60; i += TIME_PICKER_INTERVAL) {
    displayedValues.add(String.format("%02d", i));
}
mMinuteSpinner.setDisplayedValues(displayedValues
                    .toArray(new String[0]));

另见here

可以以类似的方式设置开始和结束时间,但AM / PM标志存在问题。如果你不使用am / pm但是总是以24小时格式显示时间,你的问题就解决了; - )

        if (startHour != -1 && endHour != -1) {
            Field field = classForid.getField("hour");
            NumberPicker hourSpinner = (NumberPicker) timePicker
                    .findViewById(field.getInt(null));
            hourSpinner.setMinValue(startHour);
            hourSpinner.setMaxValue(endHour);
            List<String> displayedValues = new ArrayList<String>();
            if (timePicker.is24HourView()) {
                for (int i = startHour; i <= endHour; ++i) {
                    displayedValues.add(String.format("%02d", i));
                }
            } else {
                for (int i = startHour; i <= 12; ++i) {
                    displayedValues.add(String.format("%d", i));
                }
                for (int i = 1; i <= endHour % 12; ++i) {
                    displayedValues.add(String.format("%d", i));
                }
            }
            hourSpinner.setDisplayedValues(displayedValues
                    .toArray(new String[0]));
        }