我的json数据是:
{
"guide":0,
"reunits":[
{
"residence":[
{
"name_re":"THE PORT",
"id":"88aa355ca54853640929c25c33613528"
}
]
},
{
"residence":[
{
"name_re":"KECIK",
"id":"2843543fa45857d92df3de222938e84a"
}
]
},
{
"residence":[
{
"name_re":"GREEN ANKA",
"id":"fe585cc4b4dfff1325373728929e8af9"
}
]
}
]
}
如何在jquery中通过name_re
在json数据中完成警报,值id
或each
?
我的尝试:
$.each(data.reunits, function (index, value) {
alert(value.residence.name_re); // this don't output.
})
答案 0 :(得分:3)
答案 1 :(得分:2)
这是因为它们在阵列中。您需要为每个索引访问索引0:
$.each(data.reunits, function(index, value) {
alert(value.residence[0].name_re);
});
答案 2 :(得分:1)
住所是一个数组,因此您必须执行以下js fiddle
$(document).ready(function() {
var data = {
"guide": 0,
"reunits": [
{
"residence": [
{
"name_re": "THE PORT",
"id": "88aa355ca54853640929c25c33613528"}
]},
{
"residence": [
{
"name_re": "KECIK",
"id": "2843543fa45857d92df3de222938e84a"}
]},
{
"residence": [
{
"name_re": "GREEN ANKA",
"id": "fe585cc4b4dfff1325373728929e8af9"}
]}
]
};
$.each(data.reunits, function() {
$.each(this.residence, function() {
alert(this.name_re);
alert(this.id);
});
});
});
答案 3 :(得分:0)
var data = JSON; var reunits = data.reunits; for (var i = 0, len = reunits.length; i < len; i++) { alert(reunits[i].residence[0].name_re); }
答案 4 :(得分:0)
value.residence
是一个数组。它应该是value.residence[0].name_re
。
$.each(data.reunits, function (index, value) {
alert(value.residence[0].name_re);
})