如何autowire util:list?

时间:2011-12-23 16:52:41

标签: java spring

我尝试用SpringJUnit4ClassRunner注入juni测试运行这个bean:

<util:list id="MyList" value-type="java.lang.String">
    <value>val1</value>
    <value>val2</value>
    <value>val3</value>
</util:list>

在测试用例MyTestCase中:     @Resource(mappedName =“MyList”)     @Qualifier( “MYLIST”)         private List myList;

但总是收到异常: org.springframework.beans.factory.BeanCreationException:

Error creating bean MyTestCase
...................
org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean
 of type [java.lang.String] found for dependency [collection of 
java.lang.String]: expected at least 1 bean which qualifies as autowire candidate 
for this dependency. 
Dependency annotations:   {@javax.annotation.Resource(shareable=true, 
mappedName=, description=, name=, 
type=class java.lang.Object, 
authenticationType=CONTAINER),       

 org.springframework.beans.factory.annotation.Qualifier(value=MyList)}

可能是什么原因? 感谢。

1 个答案:

答案 0 :(得分:3)

@Resource(name="MyList")
private List<String> list;

如果不起作用,请设置bean的name。如果您使用@Qualifier

,则<qualifier>注释会起作用