如何在Android中的TextView
/ EditText
中点按一下这个词。我在TextView
/ EditText
中有一些文字,当用户点击某个单词时,我想要选择该单词,之后当我调用getSelectedText()方法时,它应该返回我选中的单词字。
任何帮助将不胜感激。
我的目标是在用户点击TextView
/ EditText
中的特定字词时执行某些操作。
答案 0 :(得分:32)
更新:另一种更好的方法是使用BreakIterator
:
private void init() {
String definition = "Clickable words in text view ".trim();
TextView definitionView = (TextView) findViewById(R.id.text);
definitionView.setMovementMethod(LinkMovementMethod.getInstance());
definitionView.setText(definition, BufferType.SPANNABLE);
Spannable spans = (Spannable) definitionView.getText();
BreakIterator iterator = BreakIterator.getWordInstance(Locale.US);
iterator.setText(definition);
int start = iterator.first();
for (int end = iterator.next(); end != BreakIterator.DONE; start = end, end = iterator
.next()) {
String possibleWord = definition.substring(start, end);
if (Character.isLetterOrDigit(possibleWord.charAt(0))) {
ClickableSpan clickSpan = getClickableSpan(possibleWord);
spans.setSpan(clickSpan, start, end,
Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
}
}
}
private ClickableSpan getClickableSpan(final String word) {
return new ClickableSpan() {
final String mWord;
{
mWord = word;
}
@Override
public void onClick(View widget) {
Log.d("tapped on:", mWord);
Toast.makeText(widget.getContext(), mWord, Toast.LENGTH_SHORT)
.show();
}
public void updateDrawState(TextPaint ds) {
super.updateDrawState(ds);
}
};
}
OLD ANSWER
我想在自己的Activity中处理click。我通过以下代码解决了它:
private void init(){
String definition = "Clickable words in text view ".trim();
TextView definitionView = (TextView) findViewById(R.id.definition);
definitionView.setMovementMethod(LinkMovementMethod.getInstance());
definitionView.setText(definition, BufferType.SPANNABLE);
Spannable spans = (Spannable) definitionView.getText();
Integer[] indices = getIndices(
definitionView.getText().toString(), ' ');
int start = 0;
int end = 0;
// to cater last/only word loop will run equal to the length of indices.length
for (int i = 0; i <= indices.length; i++) {
ClickableSpan clickSpan = getClickableSpan();
// to cater last/only word
end = (i < indices.length ? indices[i] : spans.length());
spans.setSpan(clickSpan, start, end,
Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
start = end + 1;
}
}
private ClickableSpan getClickableSpan(){
return new ClickableSpan() {
@Override
public void onClick(View widget) {
TextView tv = (TextView) widget;
String s = tv
.getText()
.subSequence(tv.getSelectionStart(),
tv.getSelectionEnd()).toString();
Log.d("tapped on:", s);
}
public void updateDrawState(TextPaint ds) {
super.updateDrawState(ds);
}
};
}
public static Integer[] getIndices(String s, char c) {
int pos = s.indexOf(c, 0);
List<Integer> indices = new ArrayList<Integer>();
while (pos != -1) {
indices.add(pos);
pos = s.indexOf(c, pos + 1);
}
return (Integer[]) indices.toArray(new Integer[0]);
}
答案 1 :(得分:0)
使用Linkify,使用您自己的正则表达式来点击单词来调用您的例程。