Question

我正在尝试使用java Web服务进行简单的添加。我在将JTextField的输入转换为int时遇到问题，以便程序可以执行添加。我的代码如下。当用户输入第一个值时，他们应该点击与第二个按钮相同的第一个按钮（butta），一旦点击第二个按钮，它应该显示结果的某个位置。当我点击按钮没有取值时，整数解析似乎不起作用。

 public class Wscalcclient {
           static int aa=0, bb=0, cc=0;
        String str = new String(); 
        JTextField fielda, fieldb;
        JTextField fieldc;

        Wscalcclient()
        {  JButton butta, buttb;
           JLabel result;
           JPanel panel;

           JFrame frame  = new JFrame();
           frame.setBackground(Color.white);
           frame.setForeground(Color.black);
           frame.setSize(500,250);

           panel = new JPanel();
           panel.setBackground(Color.cyan);
           panel.setForeground(Color.black);
           panel.setLayout(new GridLayout(0,2));

           butta = new JButton("enter number a");
           buttb = new JButton("enter number b");
           result = new JLabel("result a+b=");
           fielda = new JTextField();
           fieldb = new JTextField();
           fieldc = new JTextField();

           panel.add(butta);
           panel.add(fielda);
           panel.add(buttb);
           panel.add(fieldb);
           panel.add(result);
           panel.add(fieldc);

           butta.addActionListener(new GetA());
           buttb.addActionListener(new GetB());

           frame.getContentPane().add(panel);
           frame.pack();
           frame.setVisible(true);

        }

        class GetA implements ActionListener
        { public void actionPerformed(ActionEvent t1e)
          { aa = Integer.parseInt(fielda.getText()); }
        }

        class GetB implements ActionListener
        { public void actionPerformed(ActionEvent t1e)
          { bb = Integer.parseInt(fieldb.getText()); }
        }

        /**
         * @param args the command line arguments
         */
        public static void main(String[] args) {
            try
          { new Wscalcclient();
              calc.Calculator_Service service = new calc.Calculator_Service();
            calc.Calculator port = service.getCalculatorPort();


            BufferedReader keybrd = new BufferedReader(new InputStreamReader(System.in));
            System.out.println("enter number a: ");
            int a = Integer.parseInt(keybrd.readLine());
            System.out.println("enter number b: ");
            int b= Integer.parseInt(keybrd.readLine());

            int cc = port.add(a,b);
            System.out.println("sum = " + cc);
          }
          catch (Exception ex)
          { System.out.println("exception = " + ex);
          }
        }
    }

Answer 1

您在bb中设置了aa和ActionListener。你永远不会再检查（“读”）这些值。那么你怎么知道他们得到了错误的价值呢？您没有任何实际使用它们的代码。

整数解析int无效

1 个答案: