Question

我有一个计时器应用程序，我想在计时器完成后振动手机。我可以播放声音，直到按下OK按钮，但它只振动一次。在用户按下OK按钮之前，如何重复振动？

这是我目前的代码

SoundEffectInstance alarmSound = PlaySound(@"Alarms/"+alarmSoundString);

VibrateController vibrate = VibrateController.Default;

vibrate.Start(new TimeSpan(0,0,0,0,1000));

MessageBoxResult alarmBox = MessageBox.Show("Press OK to stop alarm", "Timer Finished", MessageBoxButton.OK);

if (alarmBox == MessageBoxResult.OK)
{
    alarmSound.Stop();
    vibrate.Stop();
}

更新：我已经尝试了Joe的回复，如果我不打电话MessageBox.Show()，它会起作用。在按下OK之前，它似乎停止了。

Answer 1

如果传递大于5秒的值，

VibrateController.Start(Timespan)将抛出错误，因此您需要做一些技巧来保持它。创建一个计时器，并将其设置为重新启动振动。例如：

<强>编辑

愚蠢的我，我忘记了Messagebox和DispatcherTimer都将在同一个线程上运行。 Messagebox将阻止它。试试这个。

public partial class MainPage : PhoneApplicationPage
{
    TimeSpan vibrateDuration = new TimeSpan(0, 0, 0, 0, 1000);
    System.Threading.Timer timer;
    VibrateController vibrate = VibrateController.Default;
    int timerInterval = 1300;
    SoundEffectInstance alarmSound = PlaySound(@"Alarms/"+alarmSoundString);
    TimeSpan alramDuration; //used to make it timeout after a while

    public MainPage()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        timer = new Timer(new TimerCallback(timer_Tick), null, 0, timerInterval);
        alramDuration = TimeSpan.FromSeconds(0);
        alarmSound.Play();
        MessageBoxResult alarmBox = MessageBox.Show("Press OK to stop alarm", "Timer Finished", MessageBoxButton.OK);

        if (alarmBox == MessageBoxResult.OK)
        {
            StopAll();
        }
    }

    void timer_Tick(object sender)
    {
        //keep track of how long it has been running
        //stop if it has gone too long
        //otheriwse restart

        alramDuration = alramDuration.Add(TimeSpan.FromMilliseconds(timerInterval)); 
        if (alramDuration.TotalMinutes > 1)
            StopAll();
        else
            vibrate.Start(vibrateDuration);
    }

    void StopAll()
    {
        timer.Change(Timeout.Infinite, Timeout.Infinite);
        vibrate.Stop();
        alarmSound.Stop();
    }
}

所以我使用的是System.Threading.Timer而不是Dispatcher。它主要是相同的，只是少了一个明显的API。而不是调用Start() and Stop()，你必须传递延迟金额。要开始它，传入0.它将每1.3秒继续关闭，直到你通过Timeout.Infinite Change()传递

有几点需要注意：

vibrate.Start(vibrateDuration)仅在事件中。那是因为Timer会立即启动。
根据Mystere Man's建议，我添加了超时。你会想要这样的东西。
您可能想要重构并清理我的示例

Answer 2

SoundEffectInstance alarmSound = PlaySound(@"Alarms/"+alarmSoundString);

VibrateController vibrate = VibrateController.Default;

var vibrationLength = 1000;
var startTime = DateTime.Now;
vibrate.Start(new TimeSpan(0,0,0,0,vibrationLength));

MessageBoxResult alarmBox = MessageBox.Show("Press OK to stop alarm", "Timer Finished", MessageBoxButton.OK);
var ok = false;

While (!ok){
  if (alarmBox == MessageBoxResult.OK)
  {
    ok = true;
  }
  else{
     if(startTime.AddMilliseconds(vibrationLength * 1.2) < DateTime.Now)
     {
        startTime = DateTimne.Now;
        vibrate.Start(new TimeSpan(0,0,0,0,vibrationLength));
     }
  }
}

alarmSound.Stop();
vibrate.Stop();

粗略

我不会为Windows手机编写代码，因此这可能会导致手机无法响应。但是一般的想法是继续检查以确定用户是否已经好了，如果没有，如果自从上一次振动开始新的时间以来已经有足够的时间用完了。

如果你想要脉冲我会建议使用AddMilliseconds并添加一个大于你想要的脉冲长度的长度。

改为使用计时器

假装你的课看起来像这样

public class buzzz
{

   MessageBoxResult alarmBox;
   DispatchTimer alarmTimer = new DispatchTimer();
   var vibrationLength = 1000.0;
   var timerIncrease = 1.2;
   VibrateController vibrate = VibrateController.Default;

   public buzz()
   {
      alarmTimer.Interval = TimeSpan.FromMillseconds(vibrationLegnth * timerIncrease);
      alarmTimer.Tick += alarmTimer_Tick
   }
   public void startBuzz()
   {
       SoundEffectInstance alarmSound = PlaySound(@"Alarms/"+alarmSoundString);
       vibrate.Start(new TimeSpan(0,0,0,0,vibrationLength));
       alarmTimer.Start();
       alarmBox = MessageBox.Show("Press OK to stop alarm", "Timer Finished", MessageBoxButton.OK);
    }

    void alarmTimer_Tick(object sender, EventArgs e)
        {
           if(alarmBox == MessageBoxResult.OK)
           {
              alarmTimer.Stop();
              vibrate.Stop();
           }
           else
           {
               vibrate.Start(new TimeSpan(0,0,0,0,vibrationLength));
           }
        }
}

振动，直到消息框关闭Windows Phone 7

2 个答案: