Question

我正在制作一个简单的程序，它抽象出复数和复数运算。我开始使用整数数据类型来解释我复杂数字的想象和真实方面，因为我在编码加法，减法和乘法成功之后我非常无知，我意识到对于除法我需要使用双精度。当我切换到双打时，我的前三次计算结果很差，当值存储为整数时，这些计算非常有用。有人可以向我解释一下c ++中的int和double有什么根本不同的东西让我的代码在int中工作正常但在我尝试使用双精度时会死掉吗？

我已粘贴我的代码供参考。

 #include "Complex.h"
#include <math.h>
#include <stdio.h>
#include <stdlib.h>


Complex::Complex(){
    real = 0;
    imaginary = 0;
}
Complex::Complex(double givenReal, double givenImaginary)
{
    real = givenReal;
    imaginary = givenImaginary;
}
double Complex::getImaginary(){
    return imaginary;
}
double Complex::getReal(){
    return real;
}
double Complex::getMagnitude(){
    //magnitude = sqrt(pow(real,2)+pow(magnitude,2));
    return magnitude;
}

Complex Complex::operator+(Complex n){
    Complex j = Complex();
    j.real = real + n.real;
    j.imaginary = imaginary + n.imaginary;
    return j;
}
Complex Complex::operator-(Complex n){
    Complex j = Complex();
    j.real = real - n.real;
    j.imaginary = imaginary - n.imaginary;
    return j;
}
Complex Complex::operator*(Complex n){
    Complex j = Complex();
    j.real = (real * n.real)-(imaginary * n.imaginary);
    j.imaginary = (real * n.imaginary) + (imaginary * n.real);
    return j;
}
Complex Complex::operator/(Complex n){
    Complex j = Complex();
    j.real = ((real * n.real) + (imaginary * n.imaginary))/(n.real*n.real + n.imaginary*n.imaginary);
    j.imaginary = ((imaginary*n.real)-(real * n.imaginary))/(n.real*n.real + n.imaginary*n.imaginary);
    return j;
}

int main(){

    Complex a = Complex(1, 3);
    Complex b = Complex(4, 8);
    Complex c = a+b;
    printf("Adding a and b\nExpected: (5,11)\nActual: (%d,%d)\n",c.getReal(), c.getImaginary());
    c = a-b;
    printf("Subtracting b from a\nExpected: (-3,-5)\nActual: (%d,%d)\n",c.getReal(), c.getImaginary());
    c = a*b;
    printf("Multiplying a and b\nExpected: (-20,20)\nActual: (%d,%d)\n",c.getReal(), c.getImaginary());
    c = a/b;
    printf("Dividing a by b\nExpected: (.35,.05)\nActual: (%d,%d)\n",c.getReal(), c.getImaginary());
    system ("pause");
}

输出：
添加a和b
预期：（5,11）
实际：（0,1075052544）
从中减去b 预期：（ - 3，-5）
实际：（0，-1073217536）
乘以a和b
预期：（ - 20,20）
实际：（0，-1070333952）
除以b b 预期：（。35，。05）
实际：（1610612736,1071015526）

Answer 1

每个C / C ++程序员应该了解的printf格式说明符是：%d适用于int，%f适用于double。

C ++ Visual Studio中int和double的区别

1 个答案: