Question

我有一个名为movies的表和一个名为movie_id的列。我想在表格中找到最常见的movie_id。

列中的示例数据：

所以结果应该是234，因为它的行数最多。我从来没有尝试过，所以我真的不知道如何实现这一目标。

Answer 1

取决于sql可能类似

SELECT * FROM movies
WHERE
 movie_id=(SELECT movie_id FROM movies GROUP BY movie_id ORDER BY count(*) DESC LIMIT 1)

也就是说，如果我理解你正在寻找什么。

Answer 2

对于MySQL：

SELECT movie_id
FROM movies
GROUP BY movie_id
ORDER BY COUNT(*) DESC
LIMIT 1

对于SQL-Server：

SELECT TOP 1 
    movie_id
FROM movies
GROUP BY movie_id
ORDER BY COUNT(*) DESC

如果您想要返回所有并列（顶部）电影：

SELECT movie_id
FROM movies
GROUP BY movie_id
HAVING COUNT(*) =
    ( SELECT TOP 1  COUNT(*)
      FROM movies
      GROUP BY movie_id
      ORDER BY COUNT(*) DESC
    )

Answer 3

SELECT movie_id FROM (
  SELECT
    movie_id,
    count(*) AS num
  FROM <tablename>
  GROUP BY movie_id
) AS baseview
ORDER BY num DESC
LIMIT 1

Answer 4

对于 SQL-Server ，请使用：

SELECT TOP 1 COUNT(*) as cnt
FROM movies
GROUP BY(movie_id)
ORDER BY cnt DESC

SQL从具有最多行的列中检索数据

4 个答案: