如何从1天，1周的数据库中选择信息？

Question

我需要修改我的查询以选择1天，1周的信息。 我有2个表用于投票，其他用于文章，它应该从文章表中查看st_date。

查询

SELECT stories.*, SUM(votes.vote_value) as 'total_votes' 
FROM stories 
    JOIN votes ON stories.id = votes.item_name 
GROUP BY stories.id 
ORDER BY total_votes DESC LIMIT 10

数据库结构：

故事表

投票表

Answer 1

一周总是7天，所以你实际上需要8天的数据。

WHERE st_date >= DATE_SUB(NOW(), INTERVAL 8 DAY)

您的完整查询将是：

SELECT stories.*, SUM(votes.vote_value) as 'total_votes' 
FROM stories 
    JOIN votes ON stories.id = votes.item_name 
WHERE stories.st_date >= DATE_SUB(NOW(), INTERVAL 8 DAY)
GROUP BY stories.id 
ORDER BY total_votes DESC LIMIT 10

Answer 2

看起来像......

WHERE st_date＆gt; =现在，间隔8天

Answer 3

您需要添加WHERE语句

之类的东西

SELECT stories.*, SUM(votes.vote_value) as 'total_votes' 
FROM stories 
JOIN votes ON stories.id = votes.item_name 
WHERE PERIOD_DIFF(CURRENT_DATE , stories.st_date) <  1
GROUP BY stories.id 
ORDER BY total_votes DESC LIMIT 10

Answer 4

您可以使用DATEDIF() mysql函数

来完成此操作

Answer 5

您可以在任何日期范围之间找到结果

st_date >= start_date AND st_date <=end_date