我很难尝试使用webclient
对accounts.google.com进行身份验证我正在使用C#WebClient对象来实现以下目标。
我正在将表单字段提交到https://accounts.google.com/ServiceLoginAuth?service=oz
这是POST字段:
service=oz
dsh=-8355435623354577691
GALX=33xq1Ma_CKI
timeStmp=
secTok=
Email=test@test.xom
Passwd=password
signIn=Sign in
PersistentCookie=yes
rmShown=1
现在,在我提交数据之前加载登录页面时,它有以下标题:
Content-Type text/html; charset=UTF-8
Strict-Transport-Security max-age=2592000; includeSubDomains
Set-Cookie GAPS=1:QClFh_dKle5DhcdGwmU3m6FiPqPoqw:SqdLB2u4P2oGjt_x;Path=/;Expires=Sat, 21-Dec-2013 07:31:40 GMT;Secure;HttpOnly
Cache-Control no-cache, no-store
Pragma no-cache
Expires Mon, 01-Jan-1990 00:00:00 GMT
X-Frame-Options Deny
X-Auto-Login realm=com.google&args=service%3Doz%26continue%3Dhttps%253A%252F%252Faccounts.google.com%252FManageAccount
Content-Encoding gzip
Transfer-Encoding chunked
Date Thu, 22 Dec 2011 07:31:40 GMT
X-Content-Type-Options nosniff
X-XSS-Protection 1; mode=block
Server GSE
现在好了如何使用WebClient Class来包含这些标题?
我尝试了webClient_.Headers.Add();
,但效果有限并且始终返回登录页面。
以下是我使用的课程。非常感谢任何帮助。
获取登录页面
public void LoginPageRequest(Account acc)
{
var rparams = new RequestParams();
rparams.URL = @"https://accounts.google.com/ServiceLoginAuth?service=oz";
rparams.RequestName = "LoginPage";
rparams.Account = acc;
webClient_.DownloadDataAsync(new Uri(rparams.URL), rparams);
}
void webClient__DownloadDataCompleted(object sender, DownloadDataCompletedEventArgs e)
{
RequestParams rparams = (RequestParams)e.UserState;
if (rparams.RequestName == "LoginPage")
{
ParseLoginRequest(e.Result, e.UserState);
}
}
现在使用HtmlAgilityPack获取表单字段并将它们添加到Parameters集合
中 public void ParseLoginRequest(byte[] data, object UserState)
{
RequestParams rparams = (RequestParams)UserState;
rparams.ClearParams();
ASCIIEncoding encoder = new ASCIIEncoding();
string html = encoder.GetString(data);
HtmlNode.ElementsFlags.Remove("form");
HtmlDocument doc = new HtmlDocument();
doc.LoadHtml(html);
HtmlNode form = doc.GetElementbyId("gaia_loginform");
rparams.URL = form.GetAttributeValue("action", string.Empty);
rparams.RequestName = "LoginPost";
var inputs = form.Descendants("input");
foreach (var element in inputs)
{
string name = element.GetAttributeValue("name", "undefined");
string value = element.GetAttributeValue("value", "");
if (!name.Equals("undefined")) {
if (name.ToLower().Equals("email"))
{
value = rparams.Account.Email;
}
else if (name.ToLower().Equals("passwd"))
{
value = rparams.Account.Password;
}
rparams.AddParam(name,value);
Console.WriteLine(name + "-" + value);
}
}
webClient_.UploadValuesAsync(new Uri(rparams.URL),"POST", rparams.GetParams,rparams);
发布数据后,我获得了登录页面而不是重定向或成功消息。
我做错了什么?
答案 0 :(得分:4)
在一些摆弄之后,看起来WebClient类不是解决这个特定问题的最佳方法。
为了达到以下目标,我必须跳到WebRequest下面的一个级别。
在制作WebRequest(HttpWebRequest)并使用HttpWebResponse时,可以设置CookieContainer
webRequest_ = (HttpWebRequest)HttpWebRequest.Create(rparams.URL);
webRequest_.UserAgent = "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322; .NET CLR 2.0.50727)";
CookieContainer cookieJar = new CookieContainer();
webRequest_.CookieContainer = cookieJar;
string html = string.Empty;
try
{
using (WebResponse response = webRequest_.GetResponse())
{
using (var streamReader = new StreamReader(response.GetResponseStream()))
{
html = streamReader.ReadToEnd();
ParseLoginRequest(html, response,cookieJar);
}
}
}
catch (WebException e)
{
using (WebResponse response = e.Response)
{
HttpWebResponse httpResponse = (HttpWebResponse)response;
Console.WriteLine("Error code: {0}", httpResponse.StatusCode);
using (var streamReader = new StreamReader(response.GetResponseStream()))
Console.WriteLine(html = streamReader.ReadToEnd());
}
}
然后以后续方式使用相同的Cookie容器时
webRequest_ = (HttpWebRequest)HttpWebRequest.Create(rparams.URL);
webRequest_.UserAgent = "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322; .NET CLR 2.0.50727)";
webRequest_.Method = "POST";
webRequest_.ContentType = "application/x-www-form-urlencoded";
webRequest_.CookieContainer = cookieJar;
var parameters = new StringBuilder();
foreach (var key in rparams.Params)
{
parameters.AppendFormat("{0}={1}&",HttpUtility.UrlEncode(key.ToString()),
HttpUtility.UrlEncode(rparams.Params[key.ToString()]));
}
parameters.Length -= 1;
using (var writer = new StreamWriter(webRequest_.GetRequestStream()))
{
writer.Write(parameters.ToString());
}
string html = string.Empty;
using (response = webRequest_.GetResponse())
{
using (var streamReader = new StreamReader(response.GetResponseStream()))
{
html = streamReader.ReadToEnd();
}
}
因此,这个代码不适合生产使用,可以/应该进行优化。 以此为例。
答案 1 :(得分:3)
这是一个在答案窗格中编写并且未经测试的快速示例。您可能需要从一些表单值的初始请求中解析一些值以进入formData。我的很多代码都基于这种类型的进程,除非我们需要刮掉facebook speako类型的站点,在这种情况下,ajax使我们使用不同的方法。
using System;
using System.Collections.Generic;
using System.Collections.Specialized;
using System.Linq;
using System.Text;
namespace GMailTest
{
class Program
{
private static NameValueCollection formData = new NameValueCollection();
private static CookieAwareWebClient webClient = new CookieAwareWebClient();
static void Main(string[] args)
{
formData.Clear();
formData["service"] = "oz";
formData["dsh"] = "-8355435623354577691";
formData["GALX"] = "33xq1Ma_CKI";
formData["timeStmp"] = "";
formData["secTok"] = "";
formData["Email"] = "test@test.xom";
formData["Passwd"] = "password";
formData["signIn"] = "Sign in";
formData["PersistentCookie"] = "yes";
formData["rmShown"] = "1";
byte[] responseBytes = webClient.UploadValues("https://accounts.google.com/ServiceLoginAuth?service=oz", "POST", formData);
string responseHTML = Encoding.UTF8.GetString(responseBytes);
}
}
public class CookieAwareWebClient : WebClient
{
public CookieAwareWebClient() : this(new CookieContainer())
{ }
public CookieAwareWebClient(CookieContainer c)
{
this.CookieContainer = c;
this.Headers.Add("User-Agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/536.5 (KHTML, like Gecko) Chrome/19.0.1084.52 Safari/536.5");
}
public CookieContainer CookieContainer { get; set; }
protected override WebRequest GetWebRequest(Uri address)
{
WebRequest request = base.GetWebRequest(address);
if (request is HttpWebRequest)
{
(request as HttpWebRequest).CookieContainer = this.CookieContainer;
}
return request;
}
}
}