我正在尝试连接到MySQL数据库以在TextView中显示一些信息。我一直在尝试本教程,但我一直在努力。我的PHP应该没问题。我关心的是处理数据。我对C#比对Java更熟悉,所以这可能是我的困惑开始的地方。
这是我到目前为止所做的:
package shc_BalloonSat.namespace;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
//import android.view.View;
import org.json.JSONArray;
import org.json.JSONException;
public class Shc_BalloonSat_Activity extends Activity
{
int historyCountFromUser;
/** Called when the activity is first created. */
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
assignInfoToInfoTextView();
assignInfoToHistoryTextView();
}
public void assignInfoToInfoTextView()
{
connect2DB();
JSONArray jArray = new JSONArray(result);
TextView infoTV = (TextView)this.findViewById(R.id.info);
String infoText = "Last Known Altitude: " + /*put db info here*/ /*+*/ "\n";
infoText += "Last Known Speed: " + /*put db info here*/ /*+*/ "\n";
infoText += "Last Known Latitude:" + /*put db info here*/ /*+*/ "\n";
infoText += "Last Known Longtitude: " + /*put db info here*/ /*+*/ "\n";
infoTV.setText(infoText);
}
public void assignInfoToHistoryTextView()
{
connect2DB();
JSONArray jArray = new JSONArray(result);
for (int count = 0; count <= 4; count++)
{
TextView historyTV = (TextView)this.findViewById(R.id.history);
String historyText = "Altitude: " + /*put db info here*/ /*+*/ "\n";
historyText += "Speed: " + /*put db info here*/ /*+*/ "\n";
historyText += "Latitude:" + /*put db info here*/ /*+*/ "\n";
historyText += "Longtitude: " + /*put db info here*/ /*+*/ "\n\n";
historyTV.append(historyText);
}
}
@SuppressWarnings("null")
public void connect2DB()
{
String result = "";
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
// Get data from database using HTTP Post
try
{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("\* link to php file goes here */");
httppost.setEntity(newUrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = new response.getEntity();
InputStream is = entity.getContent();
}
catch (Exception e)
{
Log.e("log_tag", "Error in HTTP connection ");
}
// Convert the data to a string that the phone can read
try
{
InputStream is = null;
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
is.close();
result = sb.toString();
}
catch (Exception e)
{
Log.e("log_tag", "Error converting result ");
}
// Parse data
catch (JSONException e)
{
Log.e("log_tag", "Error parsing data "+e.toString());
}
}
private HttpEntity newUrlEncodedFormEntity(
ArrayList<NameValuePair> nameValuePairs)
{
// TODO Auto-generated method stub
return null;
}
}
我的查询从数据库中提取最后5个条目。我希望最后一个进入常规功能,所有其他4进入历史功能,但按照降序排列,从最新的条目到最旧的。它看起来像我正确的方式吗?
答案 0 :(得分:1)
您没有尝试连接到数据库。您正在尝试将数据发布到Web服务。如果您正在获得结果,那么您的客户端代码就可以了,并且您没有连接问题。
如果您的实际问题与拆分结果并将其放入不同位置有关,那么您必须告诉我们结果是什么样的。