考虑到我不想使用curl,这是发布帖子请求的有效替代方法吗?也许Zend_http_client
?
我只需要基本的东西(我需要一个只有一个帖子参数的网址)
答案 0 :(得分:31)
您可以使用file_get_contents()。
PHP手册有一个很好的example here。这只是从手册中复制过来的:
$postdata = http_build_query(
array(
'var1' => 'some content',
'var2' => 'doh'
)
);
$opts = array('http' =>
array(
'method' => 'POST',
'header' => 'Content-type: application/x-www-form-urlencoded',
'content' => $postdata
)
);
$context = stream_context_create($opts);
$result = file_get_contents('http://example.com/submit.php', false, $context);
答案 1 :(得分:2)
您可以通过套接字自行实现:
$url = parse_url(''); // url
$requestArray = array('var' => 'value');
$sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP);
socket_connect($sock, $url['host'], ((isset($url['port'])) ? $url['port'] : 80));
if (!$sock) {
throw new Exception('Connection could not be established');
}
$request = '';
if (!empty($requestArray)) {
foreach ($requestArray as $k => $v) {
if (is_array($v)) {
foreach($v as $v2) {
$request .= urlencode($k).'[]='.urlencode($v2).'&';
}
}
else {
$request .= urlencode($k).'='.urlencode($v).'&';
}
}
$request = substr($request,0,-1);
}
$data = "POST ".$url['path'].((!empty($url['query'])) ? '?'.$url['query'] : '')." HTTP/1.0\r\n"
."Host: ".$url['host']."\r\n"
."Content-type: application/x-www-form-urlencoded\r\n"
."User-Agent: PHP\r\n"
."Content-length: ".strlen($request)."\r\n"
."Connection: close\r\n\r\n"
.$request."\r\n\r\n";
socket_send($sock, $data, strlen($data), 0);
$result = '';
do {
$piece = socket_read($sock, 1024);
$result .= $piece;
}
while($piece != '');
socket_close($sock);
// TODO: Add Header Validation for 404, 403, 401, 500 etc.
echo $result;
当然,你必须改变它以满足你的需要或将它包装成一个函数。
答案 2 :(得分:2)
您可以使用stream_context_create和file_get_contents
<?php
$context_options = array (
'http' => array (
'method' => 'POST',
'header'=> "Content-type: application/x-www-form-urlencoded\r\n"
. "Content-Length: " . strlen($data) . "\r\n",
'content' => $data
)
);
?>
$context = stream_context_create($context_options);
$data = file_get_contents('http://www.php.net', false, $context);
答案 3 :(得分:0)
如果您使用pecl_http配置PHP,最简单的方法是:
$response = http_post_data($url, $post_params_string);
该功能记录在php.net上:
PECL还提供了一个记录良好的方法来处理POST之前的Cookie,重定向,身份验证等:
答案 4 :(得分:-1)
RESTclient是一个不错的小应用程序:http://code.google.com/p/rest-client/
答案 5 :(得分:-3)
如果您已经使用了Zend Framework,那么您应该尝试一下您提到的Zend_Http_Client:
$client = new Zend_Http_Client($host, array(
'maxredirects' => 3,
'timeout' => 30));
$client->setMethod(Zend_Http_Client::POST);
// You might need to set some headers here
$client->setParameterPost('key', 'value');
$response = $client->request();