如何在没有卷曲的情况下发帖请求?

时间:2011-12-21 21:03:21

标签: php http

考虑到我不想使用curl,这是发布帖子请求的有效替代方法吗?也许Zend_http_client

我只需要基本的东西(我需要一个只有一个帖子参数的网址)

6 个答案:

答案 0 :(得分:31)

您可以使用file_get_contents()。

PHP手册有一个很好的example here。这只是从手册中复制过来的:

$postdata = http_build_query(
    array(
        'var1' => 'some content',
        'var2' => 'doh'
    )
);
$opts = array('http' =>
    array(
        'method'  => 'POST',
        'header'  => 'Content-type: application/x-www-form-urlencoded',
        'content' => $postdata
    )
);
$context  = stream_context_create($opts);
$result = file_get_contents('http://example.com/submit.php', false, $context);

答案 1 :(得分:2)

您可以通过套接字自行实现:

    $url = parse_url(''); // url
    $requestArray = array('var' => 'value');
    $sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP);
    socket_connect($sock, $url['host'], ((isset($url['port'])) ? $url['port'] : 80));
    if (!$sock) {
        throw new Exception('Connection could not be established');
    }

    $request = '';
    if (!empty($requestArray)) {
        foreach ($requestArray as $k => $v) {
            if (is_array($v)) {
                foreach($v as $v2) {
                    $request .= urlencode($k).'[]='.urlencode($v2).'&';
                }
            }
            else {
                $request .= urlencode($k).'='.urlencode($v).'&';
            }
        }
        $request = substr($request,0,-1);
    }
    $data = "POST ".$url['path'].((!empty($url['query'])) ? '?'.$url['query'] : '')." HTTP/1.0\r\n"
    ."Host: ".$url['host']."\r\n"
    ."Content-type: application/x-www-form-urlencoded\r\n"
    ."User-Agent: PHP\r\n"
    ."Content-length: ".strlen($request)."\r\n"
    ."Connection: close\r\n\r\n"
    .$request."\r\n\r\n";
    socket_send($sock, $data, strlen($data), 0);

    $result = '';
    do {
        $piece = socket_read($sock, 1024);
        $result .= $piece;
    }
    while($piece != '');
    socket_close($sock);
    // TODO: Add Header Validation for 404, 403, 401, 500 etc.
    echo $result;

当然,你必须改变它以满足你的需要或将它包装成一个函数。

答案 2 :(得分:2)

您可以使用stream_context_createfile_get_contents

<?php
$context_options = array (
        'http' => array (
            'method' => 'POST',
            'header'=> "Content-type: application/x-www-form-urlencoded\r\n"
                . "Content-Length: " . strlen($data) . "\r\n",
            'content' => $data
            )
        );
?>


$context = stream_context_create($context_options); 
$data = file_get_contents('http://www.php.net', false, $context);

答案 3 :(得分:0)

如果您使用pecl_http配置PHP,最简单的方法是:

$response = http_post_data($url, $post_params_string);

该功能记录在php.net上:

PECL还提供了一个记录良好的方法来处理POST之前的Cookie,重定向,身份验证等:

http://php.net/manual/en/http.request.options.php

答案 4 :(得分:-1)

RESTclient是一个不错的小应用程序:http://code.google.com/p/rest-client/

答案 5 :(得分:-3)

如果您已经使用了Zend Framework,那么您应该尝试一下您提到的Zend_Http_Client

$client = new Zend_Http_Client($host, array(
            'maxredirects' => 3,
            'timeout'      => 30));
$client->setMethod(Zend_Http_Client::POST);
// You might need to set some headers here
$client->setParameterPost('key', 'value');
$response = $client->request();