以下给出的代码用于视频流。这对于IE9和Firefox来说很不错，但Chrome和Mac Safari不行。
import java.io.*;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class VideoStreamServlet
*/
public class VideoStreamServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* Default constructor.
*/
public VideoStreamServlet() {
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
String range = request.getHeader("range");
String browser = request.getHeader("User-Agent");
System.out.println(browser);
if(browser.indexOf("Firefox") != -1){
System.out.println("==========ITS FIREFOX=============");
byte[] data = getBytesFromFile(new File("D:/media/final.ogg"));
response.setContentType("video/ogg");
response.setContentLength(data.length);
response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
response.setHeader("Accept-Ranges", "bytes");
response.setHeader("Etag", "W/\"9767057-1323779115364\"");
byte[] content = new byte[1024];
BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
OutputStream os = response.getOutputStream();
while (is.read(content) != -1) {
//System.out.println("... write bytes");
os.write(content);
}
is.close();
os.close();
}
else if(browser.indexOf("Chrome") != -1){
System.out.println("==========ITS Chrome=============");
byte[] data = getBytesFromFile(new File("D:/media/final.mp4"));
String diskfilename = "final.mp4";
response.setContentType("video/mp4");
//response.setContentType("application/octet-stream");
response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
System.out.println("data.length " + data.length);
response.setContentLength(data.length);
response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
response.setHeader("Accept-Ranges", "bytes");
response.setHeader("Etag", "W/\"9767057-1323779115364\"");
byte[] content = new byte[1024];
BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
OutputStream os = response.getOutputStream();
while (is.read(content) != -1) {
//System.out.println("... write bytes");
os.write(content);
}
is.close();
os.close();
}
else if(browser.indexOf("MSIE") != -1) {
System.out.println("==========ITS IE9=============");
byte[] data = getBytesFromFile(new File("D:/media/final.mp4"));
String diskfilename = "final.mp4";
response.setContentType("video/mpeg");
//response.setContentType("application/octet-stream");
response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
System.out.println("data.length " + data.length);
response.setContentLength(data.length);
response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
response.setHeader("Accept-Ranges", "text/x-dvi");
response.setHeader("Etag", "W/\"9767057-1323779115364\"");
byte[] content = new byte[1024];
BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
OutputStream os = response.getOutputStream();
while (is.read(content) != -1) {
//System.out.println("... write bytes");
os.write(content);
}
is.close();
os.close();
}
else if( browser.indexOf("CoreMedia") != -1) {
System.out.println("============ Safari=============");
byte[] data = getBytesFromFile(new File("D:/media/final.mp4"));
String diskfilename = "final.mp4";
response.setContentType("video/mpeg");
//response.setContentType("application/octet-stream");
response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
System.out.println("data.length " + data.length);
//response.setContentLength(data.length);
//response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
// response.setHeader("Accept-Ranges", " text/*, text/html, text/html;level=1, */* ");
// response.setHeader("Etag", "W/\"9767057-1323779115364\"");
byte[] content = new byte[1024];
BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
OutputStream os = response.getOutputStream();
while (is.read(content) != -1) {
//System.out.println("... write bytes");
os.write(content);
}
is.close();
os.close();
}
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
private static byte[] getBytesFromFile(File file) throws IOException {
InputStream is = new FileInputStream(file);
//System.out.println("\nDEBUG: FileInputStream is " + file);
// Get the size of the file
long length = file.length();
//System.out.println("DEBUG: Length of " + file + " is " + length + "\n");
/*
* You cannot create an array using a long type. It needs to be an int
* type. Before converting to an int type, check to ensure that file is
* not loarger than Integer.MAX_VALUE;
*/
if (length > Integer.MAX_VALUE) {
System.out.println("File is too large to process");
return null;
}
// Create the byte array to hold the data
byte[] bytes = new byte[(int)length];
// Read in the bytes
int offset = 0;
int numRead = 0;
while ( (offset < bytes.length)
&&
( (numRead=is.read(bytes, offset, bytes.length-offset)) >= 0) ) {
offset += numRead;
}
// Ensure all the bytes have been read in
if (offset < bytes.length) {
throw new IOException("Could not completely read file " + file.getName());
}
is.close();
return bytes;
}
}
答案 0 :(得分：9)
老实说，这种做法绝对不对。
您正在嗅探服务器端的用户代理并依赖其上的业务作业。在所有情况下，这都是一个坏主意。如果你想要的是根据用户代理指定不同的文件，那么在JavaScript方面借助JavaScript或CSS来做它。两种客户端语言都能够识别真实的浏览器，而无需嗅探用户代理字符串（即可欺骗）。
您未对Range次请求做出正确回复。您正在发送完整文件而不是请求的Range。 Firefox和IE不使用范围请求，这就是它“工作”的原因。 Chrome和Safari使用范围请求。
这应该可以在不嗅探用户代理的情况下正确回复Range请求，而不是RandomAccessFile和File。考虑所有HTTP specification要求只需要很多代码，所以这里只是一个链接，您可以在其中找到这样一个servlet的具体示例：FileServlet supporting resume and caching。
但是，更好的方法是将作业委托给servletcontainer的默认servlet。如果它是例如Tomcat，那么您需要做的就是将以下行添加到byte[]：
/conf/server.xml这样，http://localhost:8080/media/final.ogg和http://localhost:8080/media/final.mp4就可以使用所需的媒体文件，而无需自行生成servlet。
答案 1 :(得分：1)
这似乎更像是一种格式支持问题。
您可以尝试ogg格式。 HTML5代码是
<audio controls="controls">
<source src="song.ogg" type="audio/ogg" />
Your browser does not support the audio tag.
</audio>
答案 2 :(得分：0)
Google Chrome不支持H.264（包括mp4），因此您还需要将final.ogg与google chrome一起使用。而对于safari，你需要改变这一行
browser.indexOf("CoreMedia") != -1
添加“Safari”而不是“CoreMedia”
我希望它有效。
答案 3 :(得分：0)
String diskfilename = "final.mp4";
response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
只需评论这两行，然后在Chrome上播放您的视频即可播放。