Question

是否可以使用url为background设置framelayout？

实施例：我想使用this之类的网址作为我的framelayout背景。

我真正希望实现的是，当我的活动加载时，它将从我的域中获取图像并将其用作我的framelayout背景图像。我能够做到这一点，但我使用了imageview和一个按钮。

下面是我使用的代码：

public class MyAppActivity extends Activity {

ImageView imView;
    String imageUrl= "http://www.mydomain.com/resource/images/";

public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);

setContentView(R.layout.main);
Button bt3= (Button)findViewById(R.id.postbutton);
bt3.setOnClickListener(getImgListener);

}
View.OnClickListener getImgListener = new View.OnClickListener()
{

      public void onClick(View view) {

           downloadFile(imageUrl+"image"+".png");
           Log.i("im url",imageUrl+"image"+".png");
      }

};


Bitmap bmImg;
void downloadFile(String fileUrl){
      URL myFileUrl =null;          
      try {
           myFileUrl= new URL(fileUrl);
      } catch (MalformedURLException e) {
           // TODO Auto-generated catch block
           e.printStackTrace();
      }
      try {
           HttpURLConnection conn= (HttpURLConnection)myFileUrl.openConnection();
           conn.setDoInput(true);
           conn.connect();
           InputStream is = conn.getInputStream();

           bmImg = BitmapFactory.decodeStream(is);
           imView.setImageBitmap(bmImg);
      } catch (IOException e) {
           // TODO Auto-generated catch block
           e.printStackTrace();
      }
 }

 }

，这是我的XML代码：

<?xml version="1.0" encoding="utf-8"?>
<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="@drawable/rakistaradiobg"
android:orientation="vertical" >

<ImageView
    android:id="@+id/imageView1"
    android:layout_width="wrap_content"
    android:layout_height="98dp"
    android:layout_gravity="bottom|center"
    android:scaleType="fitXY"
    android:src="@drawable/btnbg" />

<Button
    android:id="@+id/postbutton"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_marginTop="50dp"
    android:text="Button" />

Answer 1

感兴趣的东西，（我从不尝试过，但它应该有效）

FrameLayout fm = (FrameLayout)findViewById(R.id.FrameLayout01);      
Drawable drw = ImageOperations(this,url,filename)
fm.setBackgroundDrawable(drw)

使用

在Drawable中转换图片网址

private Drawable ImageOperations(Context ctx, String url, String saveFilename) {
        try {
            InputStream is = (InputStream) this.fetch(url);
            Drawable d = Drawable.createFromStream(is, saveFilename);
            return d;
        } catch (MalformedURLException e) {
            e.printStackTrace();
            return null;
        } catch (IOException e) {
            e.printStackTrace();
            return null;
        }
    }

    public Object fetch(String address) throws MalformedURLException,IOException {
        URL url = new URL(address);
        Object content = url.getContent();
        return content;
    }

试试这个，让我知道发生了什么......

Answer 2

您可以使用WebView来显示网站内容。 There is也是在Android开发者网站上使用WebView的精彩教程

Answer 3

这里的代码是您可以从URL

获取位图中的图像

 Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL(imageUrl).getContent());

并使用This您可以将位图转换为drawable ...

并且在获得drawable之后应用布局，如

framelyt.setBackgroundDrawable(d);

Answer 4

private RelativeLayout myRelativeLauout;

myRelativeLauout = (RelativeLayout)findViewById(R.id.rlBg);  
new LoadBackground("http://www.tmonews.com/wp-content/uploads/2012/10/androidfigure.jpg",
            "androidfigure").execute();


private class LoadBackground extends AsyncTask<String, Void, Drawable> {

    private String imageUrl , imageName;

    public LoadBackground(String url, String file_name) {
        this.imageUrl = url;
        this.imageName = file_name;
    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }

    @Override
    protected Drawable doInBackground(String... urls) {

        try {
            InputStream is = (InputStream) this.fetch(this.imageUrl);
            Drawable d = Drawable.createFromStream(is, this.imageName);
            return d;
        } catch (MalformedURLException e) {
            e.printStackTrace();
            return null;
        } catch (IOException e) {
            e.printStackTrace();
            return null;
        }
    }
    private Object fetch(String address) throws MalformedURLException,IOException {
        URL url = new URL(address);
        Object content = url.getContent();
        return content;
    }


    @Override
    protected void onPostExecute(Drawable result) {
        super.onPostExecute(result);
        myRelativeLauout.setBackgroundDrawable(result);
    }
}

通过URL更改Framelayout的背景图像

4 个答案: