Question

我正在尝试在PHP中执行存储过程，将数据插入表中并继续收到以下错误消息。

oci_execute（）[function.oci-execute]：ORA-01843：不是有效月份 ORA-06512：第1行

我自己运行了插入查询，但没有收到此错误。这是程序代码。

CREATE OR REPLACE PACKAGE trans_data AS 
  PROCEDURE INSERT_TRANSACTION_INFO(
    var_FName IN TRANSACTION.FIRST_NAME%type, 
    var_LName IN TRANSACTION.LAST_NAME%type, 
    var_DOB IN TRANSACTION.DOB%type, 
    var_InvoiceDate IN TRANSACTION.INVOICE_DATE%type, 
    var_ServiceCode IN TRANSACTION.SERVICE_CODE%type,
    var_BilledAmt IN TRANSACTION.BILLED_AMT%type,
    var_SSN IN TRANSACTION.SSN%type,
    var_ServiceDate IN TRANSACTION.SERVICE_DATE%type,
    var_VendorCode IN TRANSACTION.VENDOR_CODE%type,
    var_TransStatus IN TRANSACTION.TRANS_STATUS%type,
    var_Comp IN TRANSACTION.COMPANY%type,
    var_State IN TRANSACTION.STATE%type,
    var_Return OUT VARCHAR2
  );
END trans_data;

CREATE OR REPLACE PACKAGE BODY trans_data AS 
  PROCEDURE INSERT_TRANSACTION_INFO(
    var_FName IN TRANSACTION.FIRST_NAME%type, 
    var_LName IN TRANSACTION.LAST_NAME%type, 
    var_DOB IN TRANSACTION.DOB%type, 
    var_InvoiceDate IN TRANSACTION.INVOICE_DATE%type, 
    var_ServiceCode IN TRANSACTION.SERVICE_CODE%type,
    var_BilledAmt IN TRANSACTION.BILLED_AMT%type,
    var_SSN IN TRANSACTION.SSN%type,
    var_ServiceDate IN TRANSACTION.SERVICE_DATE%type,
    var_VendorCode IN TRANSACTION.VENDOR_CODE%type,
    var_TransStatus IN TRANSACTION.TRANS_STATUS%type,
    var_Comp IN TRANSACTION.COMPANY%type,
    var_State IN TRANSACTION.STATE%type,
    var_Return OUT VARCHAR2)
  IS
  BEGIN
    INSERT INTO TRANSACTION
      (FIRST_NAME, LAST_NAME, DOB, INVOICE_DATE, SERVICE_CODE, BILLED_AMT, 
        SSN, SERVICE_DATE, VENDOR_CODE, TRANSACTION_ID, TRANS_STATUS, COMPANY, 
        STATE)
    VALUES
      (var_FName, var_LName, to_date(var_DOB, 'MM/DD/YY'), 
        to_date(var_InvoiceDate, 'MM/DD/YY'), var_ServiceCode, var_BilledAmt, 
        var_SSN, to_date(var_ServiceDate, 'MM/DD/YY'), var_VendorCode, 
        SEQ_TRANSACTION_ID.nextval, var_TransStatus, var_Comp, var_State);
    var_return := 'PASS';
  EXCEPTION
  WHEN DUP_VAL_ON_INDEX THEN
    var_return := 'DUPE';
  WHEN OTHERS THEN
    var_return := 'FAIL';
  END INSERT_TRANSACTION_INFO;
END trans_data;

我的PHP代码收到上一页的POST，我验证了所有字段都正确传递，并将它们绑定到变量。

//setup insert statement
$stmts = OCI_Parse($c,"BEGIN ucs.trans_data.INSERT_TRANSACTION_INFO(
            :var_FName, :var_LName, :var_DOB, :var_InvoiceDate, :var_ServiceCode, :var_BilledAmt, :var_SSN, 
            :var_ServiceDate, :var_VendorCode, :var_TransStatus, :var_Comp, :var_State, :var_return); END;");

//bind input and output
OCI_Bind_By_Name($stmts, ":var_FName", $FName);
OCI_Bind_By_Name($stmts, ":var_LName", $LName);
OCI_Bind_By_Name($stmts, ":var_DOB", $DOB);
OCI_Bind_By_Name($stmts, ":var_InvoiceDate", $InvoiceDate);
OCI_Bind_By_Name($stmts, ":var_ServiceCode", $ServiceCode);
OCI_Bind_By_Name($stmts, ":var_BilledAmt", $BilledAmt);
OCI_Bind_By_Name($stmts, ":var_SSN", $SSN);
OCI_Bind_By_Name($stmts, ":var_ServiceDate", $ServiceDate);
OCI_Bind_By_Name($stmts, ":var_VendorCode", $VendorCode);
OCI_Bind_By_Name($stmts, ":var_TransStatus", $TransStatus);
OCI_Bind_By_Name($stmts, ":var_Comp", $ComCode);
OCI_Bind_By_Name($stmts, ":var_State", $State);
OCI_Bind_By_Name($stmts, ":var_return", $Return, 4);

//execute statement and add message to Return
oci_execute($stmts);
oci_commit($c);

为什么使用01/01/11日期的任何想法都会返回此消息？如果您需要我发布任何其他信息，请告诉我。

Answer 1

您在过程中为DATE参数声明了错误的类型。

您的程序使用to_date来解析日期，因此每个日期都应作为VARCHAR传递。但是你声明你的参数属于DATE类型：

var_DOB IN TRANSACTION.DOB%type, 
var_InvoiceDate IN TRANSACTION.INVOICE_DATE%type, 
var_ServiceDate IN TRANSACTION.SERVICE_DATE%type,

尝试将其更改为：

var_DOB IN VARCHAR2, 
var_InvoiceDate IN VARCHAR2, 
var_ServiceDate IN VARCHAR2,

然后看它是否有效。

需要帮助用PHP执行Oracle插入过程

1 个答案: