我正在使用bookmarklet,我正在使用HTML DOM解析器获取任何外部页面的所有照片(如前面的回答所提出的那样)。我正确地提取照片并显示在我的书签中弹出。但我对照片的相对路径有问题。
例如外部页面上的照片来源说http://www.example.com/dir/index.php
照片来源1:img source ='hostname / photos / photo.jpg' - 获取照片绝对是
照片来源2:img source ='/ photos / photo.jpg' - 没有得到,因为它不是绝对的。
我通过当前的url工作,我的意思是使用dirname或pathinfo来获取当前url的目录。但导致host / dir /(将主机作为父目录)和host / dir / index.php(host / dir作为父目录,这是正确的)之间的问题
请帮助我如何获得这些相关照片?
答案 0 :(得分:5)
已修复(添加了对仅查询字符串图像路径的支持)
function make_absolute_path ($baseUrl, $relativePath) {
// Parse URLs, return FALSE on failure
if ((!$baseParts = parse_url($baseUrl)) || (!$pathParts = parse_url($relativePath))) {
return FALSE;
}
// Work-around for pre- 5.4.7 bug in parse_url() for relative protocols
if (empty($baseParts['host']) && !empty($baseParts['path']) && substr($baseParts['path'], 0, 2) === '//') {
$parts = explode('/', ltrim($baseParts['path'], '/'));
$baseParts['host'] = array_shift($parts);
$baseParts['path'] = '/'.implode('/', $parts);
}
if (empty($pathParts['host']) && !empty($pathParts['path']) && substr($pathParts['path'], 0, 2) === '//') {
$parts = explode('/', ltrim($pathParts['path'], '/'));
$pathParts['host'] = array_shift($parts);
$pathParts['path'] = '/'.implode('/', $parts);
}
// Relative path has a host component, just return it
if (!empty($pathParts['host'])) {
return $relativePath;
}
// Normalise base URL (fill in missing info)
// If base URL doesn't have a host component return error
if (empty($baseParts['host'])) {
return FALSE;
}
if (empty($baseParts['path'])) {
$baseParts['path'] = '/';
}
if (empty($baseParts['scheme'])) {
$baseParts['scheme'] = 'http';
}
// Start constructing return value
$result = $baseParts['scheme'].'://';
// Add username/password if any
if (!empty($baseParts['user'])) {
$result .= $baseParts['user'];
if (!empty($baseParts['pass'])) {
$result .= ":{$baseParts['pass']}";
}
$result .= '@';
}
// Add host/port
$result .= !empty($baseParts['port']) ? "{$baseParts['host']}:{$baseParts['port']}" : $baseParts['host'];
// Inspect relative path path
if ($relativePath[0] === '/') {
// Leading / means from root
$result .= $relativePath;
} else if ($relativePath[0] === '?') {
// Leading ? means query the existing URL
$result .= $baseParts['path'].$relativePath;
} else {
// Get the current working directory
$resultPath = rtrim(substr($baseParts['path'], -1) === '/' ? trim($baseParts['path']) : str_replace('\\', '/', dirname(trim($baseParts['path']))), '/');
// Split the image path into components and loop them
foreach (explode('/', $relativePath) as $pathComponent) {
switch ($pathComponent) {
case '': case '.':
// a single dot means "this directory" and can be skipped
// an empty space is a mistake on somebodies part, and can also be skipped
break;
case '..':
// a double dot means "up a directory"
$resultPath = rtrim(str_replace('\\', '/', dirname($resultPath)), '/');
break;
default:
// anything else can be added to the path
$resultPath .= "/$pathComponent";
break;
}
}
// Add path to result
$result .= $resultPath;
}
return $result;
}
试验:
echo make_absolute_path('http://www.example.com/dir/index.php','/photos/photo.jpg')."\n";
// Outputs: http://www.example.com/photos/photo.jpg
echo make_absolute_path('http://www.example.com/dir/index.php','photos/photo.jpg')."\n";
// Outputs: http://www.example.com/dir/photos/photo.jpg
echo make_absolute_path('http://www.example.com/dir/index.php','./photos/photo.jpg')."\n";
// Outputs: http://www.example.com/dir/photos/photo.jpg
echo make_absolute_path('http://www.example.com/dir/index.php','../photos/photo.jpg')."\n";
// Outputs: http://www.example.com/photos/photo.jpg
echo make_absolute_path('http://www.example.com/dir/index.php','http://www.yyy.com/photos/photo.jpg')."\n";
// Outputs: http://www.yyy.com/photos/photo.jpg
echo make_absolute_path('http://www.example.com/dir/index.php','?query=something')."\n";
// Outputs: http://www.example.com/dir/index.php?query=something
我认为应该处理您可能正确遇到的所有事情,并且应该大致等同于浏览器使用的逻辑。还应该使用dirname()
来纠正您在Windows上可能遇到的任何奇怪现象。
第一个参数是您找到<img>
(或<a>
或其他)的页面的完整网址,第二个参数是{{1}的内容} / src
etc属性。
如果有人发现不起作用的东西(因为我知道你们都会试图打破它:-D),请告诉我,我会尝试解决它。
答案 1 :(得分:0)
'/'应该是基本路径。检查从dom解析器返回的第一个字符,如果它是'/',那么只需在其前面加上域名。