Question

有没有办法在反序列化期间选择不在xml文件中的属性的默认值？
如果xml文件中不存在mAge属性，我想使用默认值18.是否可以？

[DataContract]
public class Person 
{
    public Person ()
    {
    }
    [DataMember(Name = "Name")]
    public string mName { get; set; }
    [DataMember(Name = "Age")]
    public int mAge { get; set; }
    [DataMember(Name = "Single")]
    public bool mIsSingle { get; set; }
};

编辑以回答。

[DataContract]
public class Person 
{
    public Person ()
    {
    }
    [DataMember(Name = "Name")]
    public string mName { get; set; }
    [DataMember(Name = "Age")]
    public int? mAge { get; set; }
    [DataMember(Name = "Single")]
    public bool? mIsSingle { get; set; }

    [System.Runtime.Serialization.OnDeserialized]
    void OnDeserialized(System.Runtime.Serialization.StreamingContext c)
    {
        mAge = (mAge == null ? 18 : mAge); // 18 is the default value
    }
}

Answer 1

您可以使用[OnDeserialized]

当您需要修复a上的值时，请使用OnDeserializedAttribute 反序列化后的反序列化对象之前和之后的反序列化对象返回图表。

[DataContract]
 public class Person 
  {
    public Person ()
    {
    }
    [DataMember(Name = "Name")]
    public string mName { get; set; }
    [DataMember(Name = "Age")]
    public int mAge { get; set; }
    [DataMember(Name = "Single")]
    public bool mIsSingle { get; set; }



    [System.Runtime.Serialization.OnDeserialized]
    void OnDeserialized(System.Runtime.Serialization.StreamingContext c)
    {
      mAge = (mAge == 0) ?18:mAge;
    }
  }
}

编辑：来自您的评论

对于bool或int，您可以使用nullable bool and nullable int 因此，如果xml文件中缺少这些age和Single属性，那么它们也将为null。

这是我准备的快速样本

using System.Runtime.Serialization;
using System.ServiceModel;
using MySpace;
using System.ServiceModel.Channels;
using System;
namespace MySpace
{

 [DataContract]
 public class Person 
  {
    public Person ()
    {
    }
    [DataMember(Name = "Name")]
    public string mName { get; set; }
    [DataMember(Name = "Age")]
    public int? mAge { get; set; }
    [DataMember(Name = "Single")]
    public bool? mIsSingle { get; set; }



    [System.Runtime.Serialization.OnDeserialized]
    void OnDeserialized(System.Runtime.Serialization.StreamingContext c)
    {
      mAge =  (mAge == null ? 18 : mAge);
    }
  }
}
[ServiceContract]
public interface IService
{
  [OperationContract]
  Person Method(Person dd);
}

public class Service : IService
{
  public Person Method(Person dd)
  {
    return dd;
  }
}

class Program
{
  static void Main(string[] args)
  {
    string Url = "http://localhost:8000/";
    Binding binding = new BasicHttpBinding();
    ServiceHost host = new ServiceHost(typeof(Service));
    host.AddServiceEndpoint(typeof(IService), binding, Url);
    host.Open();
    ChannelFactory<IService> fac = new ChannelFactory<IService>(binding);
    fac.Open();
    IService proxy = fac.CreateChannel(new EndpointAddress(Url));
    Person d = new Person();
    d.mName = "BuzBuza";

    Console.WriteLine("Data before calling service " + (d.mAge == null ? " null " : d.mAge.Value.ToString()));
    Console.WriteLine("Data before calling service " + (d.mIsSingle == null ? "null" : d.mIsSingle.Value.ToString()));
    d = proxy.Method(d);
    fac.Close();
    host.Close();
    Console.WriteLine("Data after calling service " + (d.mAge == null ? " null " : d.mAge.Value.ToString()));
    Console.WriteLine("Data after calling service " + (d.mIsSingle == null ? "null" : d.mIsSingle.Value.ToString()));

    Console.ReadLine();
  }
}

Answer 2

使用[OnDeserializing()]

并在反序列化之前设置值。因此没有必要进行检查，这可能会出错 - 如果将mAge序列化为0，该怎么办？

Answer 3

这应该有用。

[DataContract]
 public class Person 
  {
    public Person ()
    {
    }
    [DataMember(Name = "Name")]
    public string mName { get; set; }
    [DataMember(Name = "Age")]
    public int mAge = 18;
    [DataMember(Name = "Single")]
    public bool mIsSingle { get; set; }
  };

查看this页面。

DataContract，默认DataMember值

3 个答案: