有关rails命名约定的问题

时间:2011-12-18 18:24:01

标签: ruby-on-rails naming-conventions has-many-through

我想我已经遵循了应用中的rails命名约定。但是当我在终端测试代码中时,我遇到了一些违反命名约定的错误。这是我的终端会议:

irb(main):010:0> a = _
=> #<Neighborhood id: 24, name: "Lincoln Park", created_at: "2011-12-03 20:29:00", updated_at: "2011-12-03 21:08:47", minlat: 41.91092, maxlat: 41.925658, minlng: -87.648761, maxlng: -87.636117>
irb(main):011:0> a.cta_trains
NoMethodError: undefined method `cta_trains' for #<Neighborhood:0x007fd666ee61e8>
    from /usr/local/Cellar/ruby/1.9.2-p290/lib/ruby/gems/1.9.1/gems/activemodel-3.1.1/lib/active_model/attribute_methods.rb:385:in `method_missing'

现在当我尝试a.CtaTrains:

irb(main):012:0> a.CtaTrains
  CtaTrain Load (0.4ms)  SELECT "cta_trains".* FROM "cta_trains" INNER JOIN "cta_locations" ON "cta_trains"."id" = "cta_locations"."CtaTrain_id" WHERE "cta_locations"."neighborhood_id" = 24
SQLite3::SQLException: no such column: cta_locations.CtaTrain_id: SELECT "cta_trains".* FROM "cta_trains" INNER JOIN "cta_locations" ON "cta_trains"."id" = "cta_locations"."CtaTrain_id" WHERE "cta_locations"."neighborhood_id" = 24
ActiveRecord::StatementInvalid: SQLite3::SQLException: no such column: cta_locations.CtaTrain_id: SELECT "cta_trains".* FROM "cta_trains" INNER JOIN "cta_locations" ON "cta_trains"."id" = "cta_locations"."CtaTrain_id" WHERE "cta_locations"."neighborhood_id" = 24

从我的模特:

class Neighborhood < ActiveRecord::Base

  has_many :cta_trains, :through => :cta_locations
  has_many :cta_locations, :foreign_key => :neighborhood_id

end 

class CtaTrain < ActiveRecord::Base

  has_many :neighborhoods, :through => :cta_locations
  has_many :cta_locations, :foreign_key => :cta_train_id

end

class CtaLocation < ActiveRecord::Base

  belongs_to :neighborhood
belongs_to :cta_train

end

我处于停滞状态,陷入困境,头撞在墙上等等。任何帮助都会很棒。

Rails noobie在这里....好像这一点并不明显.....

2 个答案:

答案 0 :(得分:1)

注意到您似乎在IRB中...相反,我在使用您的活动记录类时会尝试留在rails控制台中。

所以用

开始吧
bundle exec rails console

答案 1 :(得分:0)

这里需要的是一个联结表。请参阅关联has_and_belongs_to_many

联结表将存储某个Neighbourhood和某个CtaTrain之间的链接。在这里,它是CtaLocation但如果你不打算实际使用这个模型,你甚至可以不定义它。

例如,您可以通过三个表(邻域,cta_trains和cta_trains_neighbourhoods)实现它,并且只有两个模型:

class Neighbourhood
  has_and_belongs_to_many :cta_trains
end

class CtaTrain
  has_and_belongs_to_many :neighbourhoods
end
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