Question

我目前正在尝试开发一个应用程序，其中包括可以从mysql服务器发送和接收数据。

该应用程序调用一个php脚本，该脚本与mysql服务器建立连接。我已成功开发了发送部分，现在我想从mysql中检索数据并将其显示在Android手机上。

mysql表由5列组成：

bssid
building
floor
lon
lat

php文件getdata.php包含：

     <?php
     $con = mysql_connect("localhost","root","xxx");
     if(!$con)
     {
        echo 'Not connected';
        echo ' - ';

     }else
     {
     echo 'Connection Established';
     echo ' - ';
     }

     $db = mysql_select_db("android");
     if(!$db)
     {
        echo 'No database selected';
     }else
     {
        echo 'Database selected';
     }
     $sql = mysql_query("SELECT building,floor,lon,lat FROM ap_location WHERE bssid='00:19:07:8e:f7:b0'");

     while($row=mysql_fetch_assoc($sql))
     $output[]=$row;
     print(json_encode($output));

      mysql_close(); ?>

在浏览器中测试时，此部分工作正常。

用于连接到php的java代码：

    public class Database {
        public static Object[] getData(){
    String db_url = "http://xx.xx.xx.xx/getdata.php";
    InputStream is = null;
    String line = null;
    ArrayList<NameValuePair> request = new ArrayList<NameValuePair>();
    request.add(new BasicNameValuePair("bssid",bssid));
    Object returnValue[] = new Object[4];
    try
    {
        HttpClient httpclient = new DefaultHttpClient();
        HttpContext localContext = new BasicHttpContext();
        HttpPost httppost = new HttpPost(db_url);
        httppost.setEntity(new UrlEncodedFormEntity(request));
        HttpResponse response = httpclient.execute(httppost, localContext);
        HttpEntity entity = response.getEntity();
        is = entity.getContent();
    }catch(Exception e){
        Log.e("log_tag", "Error in http connection" +e.toString());
    }
    String result = "";
    try
    {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
        StringBuilder sb = new StringBuilder();

        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        result=sb.toString();
    }catch(Exception e){
        Log.e("log_tag", "Error in http connection" +e.toString());
    }
    try
    {
        JSONArray jArray = new JSONArray(result);
        JSONObject json_data = jArray.getJSONObject(0);
        returnValue[0] = (json_data.getString("building"));
        returnValue[1] = (json_data.getString("floor"));
        returnValue[2] = (json_data.getString("lon"));
        returnValue[3] = (json_data.getString("lat"));

    }catch(JSONException e){
        Log.e("log_tag", "Error parsing data" +e.toString());
    }
    return returnValue;
}

}

这是一个用于向mysql服务器发送数据的修改代码，但有些问题。我试图通过在代码中设置不同的returnValue来测试它，这表明我没有运行httpclient连接的部分。

你们能帮助我吗？

我希望这不会太令人困惑，如果你愿意，我可以尝试进一步解释。

Answer 1

使用HttpGet代替HttpPost并解析您的网址。

Answer 2

这是我一直用来获取的课程

public JSONObject get(String urlString){       
    URL currentUrl;
    try {
        currentUrl = new URL(currentUrlString);
    } catch (MalformedURLException e) {
        e.printStackTrace();
        return null;
    }

    HttpURLConnection urlConnection = null;
    InputStream in;
    BufferedReader streamReader = null;
    StringBuilder responseStrBuilder = new StringBuilder();
    String inputStr;
    try {
        urlConnection = (HttpURLConnection) currentUrl.openConnection();            
        in = new BufferedInputStream(urlConnection.getInputStream());
        streamReader = new BufferedReader(new InputStreamReader(in, "UTF-8"));
        while ((inputStr = streamReader.readLine()) != null) {
            responseStrBuilder.append(inputStr);
        }
    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        urlConnection.disconnect();
        if(null != streamReader){
            try {
                streamReader.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }

    try {
        return new JSONObject(responseStrBuilder.toString());
    } catch (JSONException e) {
        e.printStackTrace();
    }
    return null;
}

尝试使用get("http://echo.jsontest.com/key/value");

进行测试

使用php从mysql获取数据到android

2 个答案: