我正在尝试在用户点击Enter键时结束程序。由于某种原因,它似乎不起作用。当我使用“char c不等于输入键”时,它在c中输入一个额外的整数(最后输入的整数)。这段代码有什么问题?
#include <stdio.h>
#include <stdlib.h>
#define framenumber 4
int test1 =0;
int test2=1;
int main(void)
{
int mainarray[framenumber][2] = {0}, nHP = 3, takein, iPT;
char c = getchar();
printf("Enter: ");
while(1)
{
char c = getchar();
if(c == '\n') {
printf("here");
}
else
{
printf("not enter\n");
takein = atoi(&c);
for (iPT = 0; mainarray[iPT][test2] != takein && iPT < framenumber; iPT++);
if (mainarray[iPT][test2] != takein)
{
//search for a victim
do {
nHP = (nHP + 1) % framenumber;
} while ( !( mainarray[nHP][test1] == 1 ? mainarray[nHP][test1] = 0 : 1 ) );
//update the page table
mainarray[nHP][test1] = 1;
mainarray[nHP][test2] = takein;
}
else
{
mainarray[iPT][test1] = 1;
}
puts("page table:");
for (iPT = 0; iPT < framenumber; iPT++)
{
printf("%s %d, %d.\n", iPT == (nHP + 1) % 4 ? ">": " ", mainarray[iPT][test1], mainarray[iPT][test2]);
}
putchar('\n');
printf("Enter: ");
}
}
return 0;
}
答案 0 :(得分:5)
不要创建块变量。 (在循环中)。
char c='\0'; /* initialize with 0 */
printf("Enter: ");
while(c!='\n') /* loop terminate condition */
{
c= getchar(); /* remove declaration */
if(c =='\n')
{
printf("here");
}
else
{
getchar(); /* read (eat) an extra input */
printf("not enter\n");
....