Question

文字档案：

$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9

如何拆分该行并获取L55894M8和L55894M9等序列号？

Answer 1

要获取第4个逗号和第9个逗号后出现的数据，您可以这样做：

var pieces = line.Split(',');
var serial1 = line[3];
var serial2 = line[8];

编辑：进一步反映后，您的文件似乎有以$开头的记录，并以下一条记录结束。如果您想要这些记录以及序列号（看起来是最后一个字段），您可以这样做：

var records = line.TrimStart('$').Split('$');
var recordObjects = records.Select(r => new { Line = r, Serial = r.TrimEnd(',').Split(',').Last() });

Answer 2

如果文件在字符串中，您可以使用字符串的.split(',')方法，然后检查结果数组的每个元素。或者，如果始终看到这种数据模式，则抓住每个第5个元素。

Answer 3

var str = "$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9";
var fieldArray = str.Split(new[] { ',' });
var serial1 = fieldArray[4];  // "L55894M8"
var serial2 = fieldArray[9];  // "L55894M9"

Answer 4

尝试正则表达式。

 string str = "$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9";
 string pat = @"L[\w]+";

 MatchCollection ar=  Regex.Matches(str, pat);

 foreach (var t in ar)
     Console.WriteLine(t);

Answer 5

在你的样本中，你的意思是希望得到索引为（4,9,14 ......）

的单词

这五个字作为一个聚会。

所以你可以这样试试......

    static void Main(string[] args)
    {
        string strSample = "$3.00,0.00,0.00,1.00,L55894M8,$3.00,0.00,0.00,2.00,L55894M9";
        var result = from p in strSample.Split(',').Select((v, i) => new { Index = i, Value = v })
                     where p.Index % 5 == 4
                     select p.Value;

        foreach (var r in result)
        {
            Console.WriteLine(r);
        }

        Console.ReadKey();
    }

如何拆分文本文件中的行

5 个答案: